Don't know how to do this please help. How many of each kind of ticket were sold?

Question

For the school play, one adult ticket costs $5.00 and one student ticket costs $3.00. Twice as many student tickets as adult tickets were sold. The total receipts were $1650.

Answer 1

Simple algebra. Let A and S be the numbers of tickets. Then we have: S = 2A; 5A+3S = 1650, and the solution from here is trivial: 5A + 6A = 1650; A = 150, and S = 300.

Answer 2

Well, $5 plus 2 x $3 equals $11. How many $11's in $1650?
150
so there were 150 adult tickets at $5 and 300 student tickets at $3 each.

That's probably not the usual way to figure it but it works!

Answer 3

I'm assuming this is for some kind of standardized test, and in such cases a quick-and-dirty solution is called for. (Skip the algebra if possible.) On such questions you can be sure no fractions are involved, and the answer is likely to be a nice round number, so start by assigning an arbitrary value -- e.g., 100 adults, 200 students. That doesn't give you enough total $$. Now double it: 200 adults, 400 students. That puts your total sales too high. Split the difference: 150 and 300. and there's your solution: $750 plus $900 = $1650. Not elegant, admittedly, but practical.

Answer 4

150 adult tickets (150 x $5.00 = $750)
300 student tickets (300 x $3.00 = $900)

Total receipts = $750 + $900 = $1,650

Answer 5

The answer is 825 tickets of each were sold, explaination, you take 1650 and divide it by 2 and there's your answer. Simple:)

Answer 6

let x = #of adult; y= #of student
x($5)+y($3)=$1650
y=2x
substituting 2x for y in equation 1
5x + 6x = 1650
11x = 1650
x=150; y=300

Answer 7

adult ticket is x , student ticket is y

5x + 3y = 1650


ignore that i'm pxssxx

Answer 8

5x+2*3x=1650
11x=1650
x=150
so 150 adult tkts and 300 children's tkts sold