vector v1 is 6.6 units long and points along the negative x axis. vector v2 is 8.5 units long and points at +45degrees to the positive x axis. a) what are the x and y components of each vector? b) determine the sum v1 and v2 (magnitude and angle)/
2006-09-18 06:14:10 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
V#____X__________Y_____
V1____-6.6_________0
V2_(sin45)*8.5___(cos45)*8.5
Vs_-6.6+.707*8.5__0+.707*8.5
Plot the tip of Vs, at x = -6.6 + .707*8.5 and y = .707*8.5 and draw in the vector from the origin to the tip. Are you expected to get magnitude and angle graphically or by trig? Anyway I'll leave that for you.
2006-09-18 06:36:39 · answer #1 · answered by sojsail 7 · 0⤊ 0⤋
x components = 6.6 cos 180^o + 8.5 cos 45^o=-6.6+6.01= - 0.59
Y components = 6.6 sin 180^o + 8.5 sin 45^o=0+6.01= 6.01
Resultant= sqrt of (x^2+y^2)=sqrt{(- 0.59)^2 + (6.01)^2}=sqrt(36.4682)=6.04 units...............................i
tan A=(y/x)=(6.01/(-0.59)=-0.179684093
angle =A + tan^-1(-0.179684093)=-10.18644068=(180 -10.18644068)=169.8 degree
2006-09-18 15:34:21 · answer #2 · answered by Amar Soni 7 · 0⤊ 0⤋
#____X__________Y_____
V1____6.6_________0
V2_(sin45)*8.5___(cos45)*8.5
Vs_6.6+.707*8.5__0+.707*8.5
Plot the tip of Vs, at x = 6.6 + .707*8.5 and y = .707*8.5 and draw in the vector from the origin to the tip. .
2006-09-18 13:41:49 · answer #3 · answered by openpsychy 6 · 0⤊ 1⤋
is that algebra?
2006-09-18 13:17:46 · answer #4 · answered by Drexme 2 · 0⤊ 0⤋