x+3y=6
slope=-1/3 and y intercept=2
put x=0,y=2
x=-3 y=3
the ordered pairs are (0,2) and (-3,3)
plot these points and run the line passing through these two points
2006-09-18 06:17:26
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answer #1
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answered by raj 7
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y = - 1/3 x + 2 is the slope intercept form
the slope is -1/3
y-intercept is +2
to draw the graph replace x and y by specific points like if x=3 solving the above equation y= -1 put point A(3,-1) on the graph
and if x= -3 solving the equation y=1 place B(-3,1) then take the ruler and draw a line between the two points ... lol
to check the graph solve for x=0 y=2 check if point C(0,2) is on the x-axis
for y=0 x=6 point D(6,0) is on the y-axis
2006-09-18 06:56:22
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answer #2
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answered by Anonymous
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1/3 x+y=2
y=-1/3 x+2
slope=-1/3=tanb angle b=tan-1(-1/3)
intercept=2
mark an intercept of 2 on y axis. with a set squre draw an angle tan-1 (-1/3) to pass thru the top point of the intercept drawn. the line obtained is the requisite graph of st.line
2006-09-18 06:50:33
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answer #3
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answered by openpsychy 6
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(1/3)x + y = 2
y = (-1/3)x + 2
slope = (-1/3)
y-intercept = 2
for a graph, go to http://www.calculator.com/calcs/GCalc.html
type in (-1/3)x + 2
2006-09-18 06:28:18
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answer #4
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answered by Sherman81 6
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y=mx+b
y=-1/3x+2
2006-09-18 06:22:50
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answer #5
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answered by swtstrbry9 3
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like i said i dont get that srry.
2006-09-18 06:17:18
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answer #6
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answered by Drexme 2
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