Find the slope of the line through the points (4, 1) and (2, 2). What are the x- intercept and y-intercept?

Answer 1

passing through (4,1),(2,2)
equation y-1/1=x-4/-2
cross multiplying -2y+2=x-4
x+2y-6=0
for x intercept put y=0 x=6
for y intercept put x=0 y=3

Answer 2

slope of a line formula

m = y₂- y₁/x₂- x₁

m= 1 - 2/4 - 2

m = - 1/2

The slope of a line is m = - 1/2

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This converts to a proportion problem

y - 1/1 = 2 + 4/ - 2

1(x - 4) = 2(y - 1)

Cross multiply

x - 4 = -2y + 2

x - 4 + 2y = - 2y + 2 + 2y

The addition property. Adding + 2y to both sides of the equation

x - 4 + 2y = 2

x - 4 + 2y - 2 = 2 - 2

Sbtraction property. Subtracting - 2 from both sides of the equation.

x + 2y - 6 = 0

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Solving for x

x + 2y - 6

x + 2Y - 6 + 6 = + 6

Adding + 6 to both sides of the equation

x + 2y = 6

x + 2(0) = 6

x = 6

The solution set is { 6 }

The x intercept is x = 6

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Solving for y

x + 2y = 6

0 + 2y = 6

2y/2 = 6/2

y = 3

The solution set is { 3 }

The answer is: The Y intercept is y = 3

Answer 3

the equation of a line is: y = mx + b

where m is the slope : m = (y2-y1)/(x2-x1) = (2-1)/(2-4) = - 1/2

and b is the y intercept : 2 = - 1/2 * 2 + b ; b = 3

y = - 1/2 x + 3

x-intercept is when y=0 solving the equation we get: x= 6
y-intercept is when x=0 solving our equation we get y=3

Answer 4

(4,1) and (2,2)

m = (2 - 1)/(2 - 4)
m = 1/(-2)
m = (-1/2)

(2,2), m = (-1/2)
2 = (-1/2)(2) + b
2 = -1 + b
b = 3

y = (-1/2)x + 3

0 = (-1/2)x + 3
-3 = (-1/2)x
-6 = -x
x = 6

y-intercept = 3
x-intercept = 6

Answer 5

You'd have to diagram this one.

Answer 6

You are cheating on your homework.