does anyone know how to simplify ...
√63 - 2√28 + √175??
2006-09-18 05:22:30 · 7 answers · asked by laurer 2 in Education & Reference ➔ Homework Help
the trick here is to separate the quantity under the sqr root sign.
sqr root 63 = sqr root (9x7)
we can extract 9 from under the sqr root sign as itis a perfect square
sqr root (9x7) = 3 sqr root 7
similarly for the other two terms
2 sqr root 28 = 2 sqr root (4x7) = 2 x2 sqr root 7= 4 sqr root 7
sqr root 175 = sqr root (25 x 7) = 5 sqr root 7
so we are left with
3 sqr root 7 - 4 sqr root 7 + 5 sqr root 7
now we just add
8 sqr root7 - 4 sqr root 7
= 4 sqr root 7
2006-09-18 05:34:53 · answer #1 · answered by jazideol 3 · 0⤊ 0⤋
â63 = â(21x3) = â21â3 = â(7x3)â3 = â7â3â3 = 3â7
â28 = â(4x7) = 2â7 -- 2â28 = 4â7
â175 = â(25x7) = 5â7
â63 - 2â28 + â175 = 3â7 - 4â7 + 5â7
= 4â7
2006-09-18 05:39:50 · answer #2 · answered by Helen B 5 · 0⤊ 0⤋
63 = 9 * 7
28 = 4 * 7
175 = 25 * 7
Therefore, your expression can be simplified to something like
â(9 * 7) - â(4 * 7) + â(25 * 7)
or 3â7 - 4â7 + 5â7
or just 4â7.
Cross fingers. I haven't done surds since I was in short pants, back when cave paintings were considered high art ...
2006-09-18 05:36:50 · answer #3 · answered by fiat_knox 4 · 1⤊ 0⤋
sq.rt.63 = sq.rt. 9*7 = 3sq.rt 7
sq.root 28 = sq.rt. 7*4 = 2sq.rt 7.
sq.rt. 175= sq.rt 25*7 = 5sq.rt 7
given identity = 3s.rt.7 - 4s.rt 7 + 5s.rt 7
= 8s.rt 7 - 4s.rt. 7
= 4s.rt 7
2006-09-18 07:16:27 · answer #4 · answered by macline k 2 · 0⤊ 0⤋
hi the answer is 4(7)^(1/2)
2006-09-18 05:27:32 · answer #5 · answered by Aditya 2 · 0⤊ 0⤋
10.58301
2006-09-18 05:26:29 · answer #6 · answered by ShowMeTheLite 3 · 0⤊ 0⤋
how stupid are you???? this must be the most simple of all equations.......the answer is.............. zzzzzzzzzzz
2006-09-18 05:25:09 · answer #7 · answered by paul_9_25 3 · 0⤊ 0⤋