If you throw the weight over the side of the boat, what happens to the water level WITH RESPECT TO THE SIDE OF THE TANK.
Go up, go down or stay the same. Explain your answer
2006-09-18 03:37:33 · 29 answers · asked by bwadsp 5 in Science & Mathematics ➔ Physics
What has happened! When I asked this question before I got stupid replys. Now a lot of you are getting it right. Well done!
2006-09-18 03:51:49 · update #1
Before you threw it overboard it displaced its own weight in water. Now it displaces its own volume (which is less, because it sinks). Therefore the total volume of water displaced goes down - so the water level goes down.
2006-09-18 03:40:53 · answer #1 · answered by gvih2g2 5 · 6⤊ 0⤋
I haven't looked at any other answers, but you said lots of people got it right, so I'm gonna give it a go.
1. Ignoring all other effects, putting the lead weight in the water will raise the water level.
2. Ignoring all other effects, taking the lead weight out of the boat will make the boat move up with respect to the water, displacing less water, and thus the overall water level will go down.
The answer therefore balances on which is the bigger effect, or whether they are the same.
Unfortunately I'm gonna have to resort to a guess, as I'm not quite sure. I think the amount of water displaced by the lead weight when it is in the boat is the same as the amount of water displaced when it is just in the water, and so the water level is going to stay the same with respect to the tank.
2006-09-18 14:28:27 · answer #2 · answered by Steve-Bob 4 · 0⤊ 0⤋
When you throw the weight into the water, the water level with respect to the side of the tank will go down.
The reasoning is that while the weight was in the boat, the amount of water displaced per the weight was equal to the amount of water weighing the same as the lead weight, provided that the boat was floating. When the weight was thrown into the water, the amount of water displaced is equal to the volume of the lead weight. And because the density of lead is higher then water, the displaced volume of water is less then when the weight was in the boat. The boat rises displacing less water, the weight sinks displacing some water, but not as much as was being displaced when the weight was in the boat, so the water level in the tank is lower.
If the boat was not floating, i.e., sunk, then the water level will stay the same.
2006-09-18 10:53:03 · answer #3 · answered by dokntowhy 1 · 0⤊ 0⤋
The level would stay the same, the mass of the boat is displacing the water in the tank. With the weight in the water, the same mass is still present. The water level with respect to the boat will go down since the boat has less mass and will float higher.
2006-09-18 11:47:51 · answer #4 · answered by Anonymous · 0⤊ 0⤋
The force of gravity pulls the boat down into the water and displaces a certain amount of water causing the water level to rise on the side of the tank. The boyant force pushes the boat out of the water causing it to float on top of the water. Tossing the lead weight allows the boat to rise slightly. However, the lead weight lands in the water and displaces water equal to the mass of the weight. This mass will be greater than (not equal to) the less area being displaced by the boat. This is because the boyant force is greater than the effect of gravity with respect to the boat's position on the surface of the water. Thus water on the side of the tank will rise.
2006-09-18 10:53:58 · answer #5 · answered by indybrother 2 · 0⤊ 0⤋
No change. The lead would displace the same amount of water in or out of the boat.
In the boat the boat is slightly lower. When you chuck the weight over the boat rises in the water, causing the tank water level to drop. but then the lead hits the water and the tank level goes up again to the original level.
However, all the swans will die.
2006-09-18 10:46:50 · answer #6 · answered by Michael H 7 · 0⤊ 0⤋
The gravity of the lead weight whilst on the boat will push the boat down causing the water level in the tank to rise by the cubic mass of the submerged part boat.
When the lead weight is thrown out of the boat, the boat will rise and the water level will reduce.
When the lead weight lands at the bottom of the tank, it will no longer have a gravitational influance and will only be able to dispurse it's own cubic mass (W x L x H) of water
2006-09-18 11:00:39 · answer #7 · answered by Anonymous · 0⤊ 0⤋
It goes down. The boat and lead are originally floating in the water, with the mass of the two and the mass of the displaced water being the same. If the lead is dropped in, it sinks, so the mass of the water displaced is only the density of the water times the volume of the lead block. Since the mass of the water displaced before the weight is dropped in is large than the mass of the water displaced after the weight is dropped in, the level of the water is lower relative to the sides of the tank.
2006-09-18 10:43:43 · answer #8 · answered by ? 4 · 2⤊ 0⤋
The water level will stay the same as the lead weight, when released into the tank, will cause the water in the tank to rise. But at the same time, the boat has "lost" this weight and will also rise.
2006-09-19 00:02:25 · answer #9 · answered by Kemmy 6 · 0⤊ 0⤋
the level of water will go down for the following reason
when the weight was in the boat the boat had to displace the same weight of water, now that the weight is out of the boat and on the bottom of the tank the boat will still be displacing it's same weight (though greatly reduced) but as the lead weight is not floating it is not displacing enough water to float
2006-09-18 10:46:57 · answer #10 · answered by jmather62 2 · 0⤊ 0⤋
If it is a large lead weight, most people would be unable to lift it, much less throw it overboard...a lead weight handled by most would have a negligible (if any) effect on the water level.
Or, I think the water level would go down a tiny bit, because the weight would have been causing the boat to displace more water than the weight alone.
2006-09-18 10:43:53 · answer #11 · answered by mrearly2 4 · 0⤊ 0⤋