i really like kate winslet i think shes played quite unique people in films , some of her early work was quite weird but i loved titanic and thought she suited that perfectly , i also like her cause shes not stick thin , shes normal with weight and diet issues sometimes , far better than being a victoria beckham who lives off 500 cals aday to look like a twig ..
2006-09-18 01:16:38
·
answer #1
·
answered by j.j. 5
·
0⤊
0⤋
Mine is James Stewart too alongside Jim Carrey. BQ: accepted short actor/actress? Peter Dinklage (4' 5") BQ2: accepted actor/actress who's an same accurate as you? Robert Downey Jr. (5' 9")
2016-11-27 21:36:36
·
answer #2
·
answered by ? 4
·
0⤊
0⤋
Jesse McCartney
Lindsay Loan
Tom Welling
Sara Paxton
Zac Efron
Hilary Duff
Raven Symone
2006-09-18 06:18:02
·
answer #3
·
answered by Guardian Angel Of Time 2
·
0⤊
0⤋
Rachel McAdams, Keira Knightley, Angelina Jolie.
2006-09-18 01:44:38
·
answer #4
·
answered by brian2412 7
·
0⤊
0⤋
Allan Rickman because he is so versatile and anything that he does he puts every effort into and it turns out fantastic. Truly Madly Deeply has to be my favourite from him.
Dame Judy Dench this woman is the most amazing actress from the serious to the comedy I have loved everything she has ever done and deserves her Dame-hood 100%.
2006-09-18 01:25:30
·
answer #5
·
answered by momof3 7
·
0⤊
0⤋
Angelina Jolie
2006-09-18 01:17:57
·
answer #6
·
answered by Anonymous
·
0⤊
0⤋
Christopher Eccleston.
Audrey Hepburn.
Carry Grant.
2006-09-18 01:23:59
·
answer #7
·
answered by Anonymous
·
0⤊
0⤋
1-Al Pacino
2-Robert De Niro
3- Edward Norton
4- Bruce Lee
5- Andy Lau
2006-09-18 02:09:45
·
answer #8
·
answered by Chong 3
·
0⤊
0⤋
I don't know really, changes depending on what mood I'm in and it wouldn't influence me to go see one of their movies but I do know which actors/actresses would put me off seeing a movie - Jim Carey would be top of that list
2006-09-18 01:18:27
·
answer #9
·
answered by Moo 1
·
1⤊
0⤋
Angela Basset
2006-09-18 01:15:54
·
answer #10
·
answered by UgottaBkiddinMe 5
·
0⤊
0⤋