How to calculate hybridization of molecule?

Answer 1

hybridisation is given by the formula:
H=1/2{ V + X - C + A}
V=no of valence electrons in central atom
X=no of monovalent atoms around the central atom
C= +ve charge on cation
A= -ve charge on anion

H=4==> sp^3,2==>sp,3==>sp^2,5==>sp^3d...

eg. in PH3
H=1/2(5+3-0+0)=4 ==>sp^3
in H2S
H=1/2(6+2-0+0)=4 ==>sp^3

best answer?

Answer 2

Hybridization Of Molecules

Answer 3

Hybridization Of Central Atom

Answer 4

consider the molecule ABxEy (1 atom of A, x atoms of B, and y pairs of electrons unused in a).
Now consider the general hibridization state which can be expressed as S Pw Dz (with w=3, z=1, we would have SP3D, etc)

Now, x + y = w + z + 1
While w is smaller or equal to 3, z is 0, which makes things easier.
For example, NH3 would be AB3E1
The w + z + 1 = 3 + 1, so w + z = 3 . That means w is smaller or equal to 3, so z = 0; then w = 3, meaning the hybridization is SP3.
It would be much easier to explain it in person though :)

Answer 5

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1/2 ( V + M - C + A ) V = Number of valence electrons M = Monoatomic atoms bonded to central atom C = Cationic charge A = Anionic charge

Answer 6

We can find the hybridization of the atom by finding its steric number: steric number = no of atoms bonded (to the atom you are finding the hyb. of) + lone pairs with that atom. if Steric no comes to be 4, there is sp3 hybridization in the atom. if steric no comes to be 3, there is sp2 hybridization in the atom.

Answer 7

sp power 3

Answer 8

You can use the link given below for subject calculations

Answer 9

http://en.wikipedia.org/wiki/Orbital_hybridisation
http://www.ucc.ie/academic/chem/dolchem/html/dict/hybrid.html

a nice explanation along with example