n=21.
5^21 * 4^11
= 5^21 * 2^22
= 2 * (5*2)^21
=2 * 10^21
2006-09-17 19:13:56
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answer #1
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answered by astrokid 4
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n=21
2006-09-17 19:18:07
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answer #2
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answered by RN Diva 2
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n=21. 4^11=2^22.
(5^21)(2^22)
=2(5^21)(2^21)
=2(10^21)
That gives n=21. I hope this helps, though I guess this question's already been answered be a few people....
2006-09-17 21:20:04
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answer #3
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answered by wlfgngpck 4
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(5^21)*(4^11) = 2*(10^n)
LHS = (5^21)*(2^2)^11 ( as 4 = 2^2)
= (5^21)*2^22 (as (a^b)^c = a^(bc))
= (5^21)*2*2^21( we take 2 out to make factor of 5 and 2 same)
= 2*(5^21)(2^21) (reordering)
= 2*(10)^21(as a^n*b^n = (ab)^n)
from the given condition n= 21
2006-09-17 19:14:50
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answer #4
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answered by Mein Hoon Na 7
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5^21 X 4^11 = 2X10^n
5^21 X 2^2(11) = 2X10^n
(5^21X2^22)/2 = 10^n
5^21 X 2^21 = 10^n
since they have th same power,
10^21 = 10^n
hence we have:
n = 21.
2006-09-17 20:04:08
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answer #5
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answered by siangal07 2
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(5^21) * (4^11) = 2 * 10^n
(5^21) * ((2^2)^11)
(5^21) * (2^(2 * 11))
(5^21) * (2^22)
(5^(21) * 2^(21)) * 2
((5 * 2)^21) * 2
2 * 10^21
ANS : n = 21
2006-09-17 19:57:55
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answer #6
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answered by Sherman81 6
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5^21 x 4^11 = 2 x 10^n
take common lograthim log 10 both side.
u get log5^21 + log4^11 = log2 + log10^n
remember loga^b = b loga and log10= 1
21log5 + 11 log 4 = log2 + n
21x 0.6990 + 11 x 0.6021 = 0.3010 + n
14.679 + 6.6231 - 0.3010 = n
so, n= 21.3021 - 0.3010
n= 21.0011
so take n as 21 , now n is 21.
2006-09-17 22:38:24
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answer #7
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answered by free aung san su kyi forthwith 2
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Astrokid is right
Th
2006-09-17 19:16:26
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answer #8
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answered by Thermo 6
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