2x + 1 / 5 - 3x
1 - 2x / 3x - 5
2x + 1 / 3x + 5
2x + 1 / 3x - 5
-2x + 1 / 3x + 5
2006-09-17 16:30:14 · 6 answers · asked by LOLO 1 in Science & Mathematics ➔ Mathematics
The signs are critical.. the procedure:
(2x3-3x-2)/(-3x2+x+10)
= -(2x-1)(x-2)/(x-2)(3x+5) = -(2x-1)/(3x+5)
the minus sign should be "affecting" the whole fraction... not just the 2x...
2006-09-17 16:41:04 · answer #1 · answered by kc 2 · 0⤊ 0⤋
You need to clarify whether it is the whole of the left divided by the whole of the right, also whether the 'x' between 2 numbers is an unknown or a multiplication sign. If it is a multiplication, I would give this answer: 2x2 - 3x - 2 / 10 + x - 3x2 = 4 - 3x - 2 / 10 + x - 6 = 2 - 3x / 4 + x
2016-03-17 02:32:41 · answer #2 · answered by Anonymous · 0⤊ 0⤋
2x^2 -3x - 2 / -3x^2 +x +10
(2x+1) ( x-2) / (-3x-5) (x-2)
2x+1 / -3x-5
2006-09-17 16:38:32 · answer #3 · answered by free aung san su kyi forthwith 2 · 0⤊ 0⤋
factor numerator and denominator
[(x-2)(2x+1)] / [(x-2)(-3x-5)]
=(2x+1)/(-3x-5)
or
(-2x-1)/(3x+5)
OR
- (2X+1)/(3X+5)
Did you forget a minus sign?
Check your choices again.
2006-09-17 16:46:40 · answer #4 · answered by iyiogrenci 6 · 0⤊ 0⤋
-2x -1/5 -2
2006-09-17 16:34:45 · answer #5 · answered by testtaker 2 · 0⤊ 0⤋
(2x^2-3x-2)/(-3x^2+x+10)
(2x^2-4x+x-2)/(-3x^2+6x-5x+10)
=(2x+1)(x-2)/(-3x-5)(x-2)
-(2x+1)/(3x+5)
2006-09-17 16:36:46 · answer #6 · answered by raj 7 · 0⤊ 0⤋