I have a triangle, one corner, the smallest of the three, is 30 degrees. Another angle is 90 degrees, making the other one 60 degrees. The odd side, the one opposite of the right angle, is 15 m. I need to find the other two lengths. What do you guys think? How would you get your answer?
2006-09-17 16:23:00 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Geography
Let the sides be a and b.
First, sin30 = a / 15
1 / 2 = a / 15
a = 15 / 2
a = 7.5
Next, cos30 = b / 15
sqrt3 / 2 = b / 15
1.73 / 2 = b / 15
b = 1.73 * 15 / 2
b = 12.98
Therefore the sides are 7.5 and 12.98 meters.
2006-09-17 20:52:52 · answer #1 · answered by Anonymous · 0⤊ 0⤋
It is a 3, 4, 5 triangle..... x 3
So hypotenuse is 3 x 5 = 15
Side opposite the 30° angle is 3 x 3 = 9
Side oppsite the 60° angle is 3 x 4 = 12
So the triangle sides are 9, 12 & 15 units......
2006-09-18 11:31:53 · answer #2 · answered by Barrie66 2 · 0⤊ 0⤋
The length of the leg in front of 30 degrees
sin 30 =x/15 1/2=x/15 x=15/2=7.5 m.
The length of the leg adjacent 30 degrees
cos 30=y/15
y=15. sqrt(3)/2 m.
2006-09-17 23:30:05 · answer #3 · answered by iyiogrenci 6 · 0⤊ 0⤋
The side opposite the right angle is the hypotenuse.
Starting from the 30 degree side:
The opposite leg is related by the sine (opposite over hypotenuse)
O/H=sine(30)=1/2
O=H/2=7.5m
The adjacent leg is related by the cosine (adjacent over hypotenuse)
A/H=cosine(30)=sqrt(3)/2
A=H*sqrt(3)/2=7.5sqrt(3)m
Starting from the 60 degree side :
The opposite leg is related by the sine (opposite over hypotenuse)
o/H=sine(60)=sqrt(3)/2
o=H*sqrt(3)/2=7.5sqrt(3)m
The adjacent leg is related by the cosine (adjacent over hypotenuse)
a/H=cosine(60)=1/2
a=H/2=7.5m
Note: O=a; o=A
2006-09-17 23:35:56 · answer #4 · answered by novangelis 7 · 0⤊ 0⤋
in a 30,60,90 triangle the sides are in ratio of s,s(3^.5),2s meaning the shortest side is half the hypotenuse (longest side) You can then apply pythagorean theorum to get the final side: 7.5m, ? , 15m.
2006-09-17 23:29:45 · answer #5 · answered by piercesk1 4 · 0⤊ 0⤋
xplus xsquare=15square; 3xsquare=225; x=15 herefore one side is 15 and the other is 30
2006-09-17 23:32:36 · answer #6 · answered by Anonymous · 0⤊ 1⤋
sin angle = oposite / hypotneus
cos = adjacent / hypotneus (opposite right angle)
2006-09-17 23:28:10 · answer #7 · answered by Karen R 1 · 1⤊ 0⤋
solve sin2theta plus cossquared theta equals one
2006-09-17 23:32:13 · answer #8 · answered by weirdoonee 4 · 0⤊ 1⤋
use trignometric ratios
2006-09-18 07:30:47 · answer #9 · answered by xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx 2 · 0⤊ 0⤋