When x3+3x2-2x+7 is divided by x+1, the remainder is : 7 8 9 11 13?

Answer 1

x^3 + 3x^2 -2x + 7
= (x+1)(x^2+2x-4) + 11

remainder = 11

Answer 2

if u need to find the remainder when f(x) is divided by (x-k) then it it is simply f(k) i.e., put k in place of x

now, f(x) = x3+3x2-2x+7 it is being divided by x+1
so remainder is f(-1)
(-1)3 + 3(-1)2 - 2(-1) +7
= -3+3+2+7
therefore 9 is the answer

Answer 3

NoName is correct; the answer is 11

x^3+3x^2-2x+7 can be rewritten as:

x^3 +3x^2 +2x -4x -4+11 =

x(x^2+3x+2) -4(x+1)+11 =

x(x+1)(x+2)-4(x+1)+11=

(x+1)(x(x+2)-4) + 11=

(x+1)k +11 where k = x(x+2)-4

So we see the remainder is11

Answer 4

let f(x) = x^3+3x^2-2x+7' if f(x) is divided by (x+1), the remainder is

f(-1) so, substitute -1 in x^3+3x^2-2x+7

(-1)^3 + 3 (-1)^2 -2(-1) +7

-1+3+2+7 so

the remainder is 11

Answer 5

The answer is 13

x+1=0
x=-1

remainder=(-1)^3+3(-1)^2-2(-1)+7=-1+3+2+7=13

Answer 6

(x^3 + 3x^2 - 2x + 7)/(x + 1)

-1`|`1``3``-2``|``7
````|````-1``-2``|``4
-------------------------
````|`1``2`-4``|``11

x^2 + 2x - 4 R 11

ANS 11

Answer 7

the rest theorem: while P(x) is divided with the aid of x-a, the rest is P(a) The polynomial P(x) is being divided with the aid of x+one million, or x-(-one million). the rest is P(-one million): (-one million)^3 + 3(-one million)^2 - 2(-one million) + 7 -one million + 3 + 2 + 7 11 the rest is 11.

Answer 8

If you try using long division you'd get 11. I also agree with NoName's method