well go ahead in this way
3x2-6x+9
= 3( x2-2x+3)
The expression x2-2x+3 cannot have real factors coz it discriminant is less than 0 .
therefore the answer is either 3 or x2-2x+3
2006-09-17 16:16:04
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answer #1
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answered by jammy 2
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3! (not three factorial)
(Always factor out any common factors that are in every term first, it makes the rest of the problem much easier)
So then 3x^2 - 6x + 9 = 3(x^2 -2x +3)
Can you factor what's left in parentheses? (If you're in Algebra 1, you won't need to, if you're in Algebra 2 or Precalculus, you're looking for a complex conjugate pair of factors.)
2006-09-17 23:04:27
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answer #2
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answered by selsnick 2
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15-6x or 9 depends 3x2 means 6x or 6.
2006-09-17 23:05:02
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answer #3
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answered by chanljkk 7
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3x^2 - 6x + 9 = 3(x^2 - 2x + 3)
2006-09-18 02:10:52
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answer #4
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answered by Sherman81 6
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3x^2 - 6x + 9 = 0 have no solution since 0 > b^2 - 4ac
a=3, b=-6, c=9
b^2 - 4ac = 6^2 - 4.3.9 = 36 - 108 = -72
2006-09-17 23:10:21
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answer #5
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answered by Anonymous
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6x+9? Syntax error!
2006-09-17 23:01:58
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answer #6
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answered by Bombenhagel 3
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This equation doesn't factor. It's an upward opening parabola with a minimum point at (1,6), so it doesn't cross the x-axis anywhere.
Perhaps there's a typo?
2006-09-17 23:13:29
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answer #7
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answered by Bramblyspam 7
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Jammy is the only one who is correct. He should get the 10 points. The answer is (a) on your list above.
2006-09-17 23:35:41
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answer #8
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answered by Sciencenut 7
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X can be anything if the equation doesn't equal anything.
2006-09-17 23:01:43
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answer #9
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answered by Stephanie 4
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