Displacement?

0 ⤊

Determine the displacment of a plane that is uniformly accelerated form 66 m/s to 88 m/s in 12s.

2006-09-17 15:56:02 · 3 answers · asked by Falling Star 1 in Science & Mathematics ➔ Physics

The acceleration is (88-66)/12 = 1.8333 m/s^2

Initial V is 66

D = Vo *t + .5at^2 = 66*12 + (1.8333/2)(12^2) = 924 m

2006-09-17 17:27:24 · answer #1 · answered by Steve 7 · 0⤊ 0⤋

88-66=22 m/s
t=12 s

22*12=264 m ?

2006-09-17 16:10:50 · answer #2 · answered by iyiogrenci 6 · 0⤊ 0⤋

I dont know how to do that

2006-09-17 15:59:23 · answer #3 · answered by saintssuck51 1 · 0⤊ 1⤋