A golfer takes three putts to get the ball into the hole. The first putt displaces the ball 3.66 m north, the second 1.83 m southeast, and the third 0.91 m southwest. What are (a) the magnitude, and (b) the direction of the displacement needed to get the ball in the hole on the first putt?
2006-09-17 15:41:48 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
OK, let's say your y-axis runs north-south and your x-axis east-west.
The first putt goes north 3.66m. Increase y by 3.66
The second putt goes SE 1.83m.
You're dealing with a 45-45-90 triangle, with hypotenuse 1.83
That makes the side lengths 1.294m (1.83/sqrt(2))
So the second putt increases x by 1.294 and decreases y by 1.294
The third putt goes 0.91 SW.
You're dealing with another 45-45-90 triangle, with hypotenuse 0.91.
End result: decrease x and y by 0.643 each
Add up all the putts:
x has increased by 0.651
y has increased by 1.723
Use Pythagoras to figure out part A.
Use sin, cos, or tan to figure out the direction in part B.
2006-09-17 15:56:47 · answer #1 · answered by Bramblyspam 7 · 0⤊ 0⤋
You had best do your own trig homework if you plan on passing the course ☺
Doug
2006-09-17 15:52:58 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋
That's too tough for my old brain!!
2006-09-17 15:50:27 · answer #3 · answered by Anonymous · 0⤊ 0⤋
they cant match cloths and they have beer bellys
2006-09-17 17:41:03 · answer #4 · answered by jeff d 3 · 0⤊ 0⤋