(1)a supersonic jet flying at 145 m/s is accelerated uniformly at the rate of 23.1 m/s^2 for 20.0s.
(2)the speed of sound in air is 331 m/s.
2006-09-17 15:27:18 · 7 answers · asked by Falling Star 1 in Science & Mathematics ➔ Physics
Take the 145 and add to that 23.1 times 20, which is 462. The total is 607 to answer (1).
For (2), divide this answer by 331 to get 1.834 times Mach 1 (the speed of sound)
(BTW the speed of sound is probably different at the elevations these planes fly at.)
2006-09-17 15:33:33 · answer #1 · answered by Radiosonde 5 · 0⤊ 0⤋
OK. So it's final velocity is
v = v0 + at = 145 + 23.1*20 = 145 + 462 = 607 m/s
607/331 = 1.83 times the speed of sound (or Mach 1.83)
Doug
2006-09-17 15:32:54 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋
final velocity is just a figure of speach. it comes from a movie, called final velocity. but the speed of an airplane compared to the speed of sound is called mach, pronounced mock like mocosons indians wore. a plane traveling at the speed of sound is doing moch 1, twice the speed of sound moch 2, and so on. final velocity was just what they were calling it just befor the plain crashed in the movie.
2006-09-17 15:41:09 · answer #3 · answered by bishop 1 · 0⤊ 1⤋
no aircraft could fly in such speed. the speed of sound is also wrong. check your "given" again. I once had a professor who'd used the same "given". Big argument but I pointed that "s" is the culprit. Was too embarras to admit his mistake.
2006-09-17 15:34:47 · answer #4 · answered by Liwayway 3 · 0⤊ 0⤋
vf = vi + a*t = 141 m/s + 23.8 m/s^2 * 20.7s = 634 m/s Mach = 634 m/s / 331 m/s = 1.91 Mach
2016-03-27 06:33:23 · answer #5 · answered by ? 4 · 0⤊ 0⤋
607 m/s
1.833836858006
Asking the final distance traveled is probably a better question.
2006-09-17 15:40:00 · answer #6 · answered by pbuchta 3 · 0⤊ 0⤋
607 m per sec
mach 1.834
2006-09-17 15:33:25 · answer #7 · answered by Grey Bear 2 · 0⤊ 0⤋