math problem help?

Question

can someone help me solve this?>

write in slope intercept form

passes through (3,11) and (-6,5)

Answer 1

A line is of the form

y = mx + b

m is the slope... rise over run...

(11 - 5) / (3 - (-6)) = 6 / 9 = 2/3

b is the y-intercept... graph the two points to see this

which will be 2/3 (6) + 5 = 9

equation is:

y = 2/3 x + 9



Aloha

Answer 2

Slope-intercept form is y = mx + b

Going from (-6,5) to (3,11)
x goes up 9, y goes up 6.
So m, aka slope, aka rise over run, is 6/9, or 2/3.

Hence, y = (2/3)x + b

To find b, plug in (3,11) for your (x,y).
11 = (2/3) * 3 + b
Solving for b, you get b=9.

Your equation is y = (2/3)x + 9.

Answer 3

Slope is (5-11)/(-6 - (3)) = (-6)/(-9) = 2/3 = m
So y = mx + b and y = (2/3)*x + b

To get b, plug in either of the points. I'll use (3,11)
11 = (2/3)*3 + b
11 = 2 + b
b = 9 And the final equation is
y = (2/3)*x + 9


Doug

Answer 4

To find the slope, divide dy by dx: dy = 11-5 = 6, dx = 3-(-6) = 9.

This gives us y = (6/9)x + b.

Now plug in 3 for x and 11 for y to solve for b.

Answer 5

First find the slope. Slope = (y1-y2)/(x1-x2)

Once you have the slope use the slope and one point in the equation y = mx + b. The point will be your x and y values and the slope goes in for m. You will need to solve for b.

The answer will be y=mx+b where you fill in the slope for m and the y intercept for b.

Hope this helps. Good Luck.

Answer 6

(3,11) and (-6,5)

m = (5 - 11)/(-6 - 3)
m = (-6)/(-6 + (-3))
m = (-6)/(-9)
m = (2/3)

(3,11), m = (2/3)

11 = (2/3)(3) + b
11 = 2 + b
b = 9

ANS : y = (2/3)x + 9

Answer 7

y=mx+b
m=6/9
2/3
3=2/3 11 + b
b= whatever 3- 11(2/3) is equal to.

then just rewrite y=mx+b