Put the parenthisis in the right place to solve the problem.
2^3+6-5x4=12
3^2+6+3x3+36
where do the par. go? sorry, my mom is in the hospital and my dad calculates in french..
2006-09-17 14:11:24 · 4 answers · asked by Anonymous in Education & Reference ➔ Homework Help
lol thats a problem has to be in tho, 2 numbers..
2006-09-17 14:19:00 · update #1
2^3+(6-5)x4=12
3^2+(6+3)x3=36
Check:
2^3+(6-5)x4 = 2*2*2 + (1) * 4 = 8 + 1 *4 = 8 + 4 = 12 :o)
3^2+(6+3)x3= 3*3 + (9) * 3 = 9 + 9 * 3 = 9 + 27 = 36 :o)
2006-09-17 14:22:13 · answer #1 · answered by Robert B 5 · 0⤊ 0⤋
I'm assuming that the little pointy thing means "to the power of".
So that first line would be 8 + 6 - 5 x 4 = 12.
Wouldn't the parentheses have to go like this?
8 + (6-5x4) = 12
It would be even better if you could use brackets for another level of grouping, making it much clearer what's going on.
8 + [(6-5)x4] = 12
The second one isn't an equasion, so.....??
2006-09-17 14:26:34 · answer #2 · answered by wasabi_luvva 2 · 0⤊ 0⤋
(2^3)+6-(5x4)=12
(3^2)+6=(3x3)+36
Pay more attention in class.
2006-09-17 14:21:27 · answer #3 · answered by Anonymous · 0⤊ 0⤋
its kinda confusing..
2^3+6-5(4)=12
3^2+6+3(3)+36
lol..idk,im guessin'
2006-09-17 14:18:14 · answer #4 · answered by ♥☻karma☻♥ 2 · 0⤊ 0⤋