Calculate the number of P4 Molecules that can form 2.5 g of Ca3(PO4)2. (Show How You Got it)
2006-09-17 13:51:44 · 2 answers · asked by ==== 3 in Science & Mathematics ➔ Chemistry
I'm going to assume you meant PO4 ions, so if not this answer is completely wrong. If so, however, you first need to find out the number of moles of Ca3(PO4)2 in 2.5 g. From a periodic table, you can see that Ca has a molar mass of 40.08 g.mol. P is 30.97376 g/mol, and O is 15.9994 g/mol. By calculating the proper number of each atom (3 Ca's, 2 P's, and 8 O's), you find that the entire molecule has a molar mass of 310.18272 g/mol. You then divide the mass (2.5 g) by this number to find out how many moles there are. This turns out to be 0.008059765547223 moles. now you can see from the formula that for every mole of Ca3(PO4)2 you have 2 moles of PO4. Therefore, you have 0.01611953109445 moles of PO4. Knowing the amount of moles of PO4, it is now very easy to convert it to the number of molecules if you know how many molecules are in a mole (which is 6.02X10^23). When you multiply this out, you see that there are 9.7039577188589X10^21 PO4 ions in 2.5 g of Ca3(PO4)2.(note that the ^ means "to the power of").
2006-09-17 14:18:21 · answer #1 · answered by Onyx Blackman 3 · 0⤊ 0⤋
Too many big numbers. I dont get chemistry at all. Im gonna fail this year.
2006-09-19 23:29:20 · answer #2 · answered by I run with scissors 4 · 0⤊ 0⤋