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2006-09-17 12:36:46 · 9 answers · asked by hmc_fmf88 1 in Education & Reference Homework Help

9 answers

2z+1=2z-z-3
2z+1=z-3
z+1=-3
z=-4

2006-09-17 12:41:42 · answer #1 · answered by cabjr1961 4 · 0 0

z=1

2006-09-17 19:46:35 · answer #2 · answered by Anonymous · 0 0

z=1

2006-09-17 19:39:59 · answer #3 · answered by Up your Maslow 4 · 0 0

Step 1: First, get rid of the the z+3 parentheses by -1 * (z + 3); that's what "- (z + 3)" means. You multiply -1 * z and then -1 * 3:
2z + 1 = z - [2z - z - 3]
Step 2: Perform the operations in the brackets; you can subtract and add things if they have the same letters (variables) so ... now you have the following:
2z + 1 = z - [z - 3]
Step 3: Get rid of the brackets by multiplying -1 by [z - 3] (similar to what we did in step 1; note: -1 * -3 = +3):
2z + 1 = z - z + 3
Step 4: Perform the operations on the right because we have two terms (z - z) that have the same variables (letters). Result:
2z + 1 = 3
Step 5: The ultimate goal is get z all by itself on one side of the equation. So ... next, get rid of the '+ 1' by subtracting it from both sides (you can add or subtract the same number to both sides of an equation):
2z = 2
Step 6: Now, to get z by itself, we have to remove the 2 in 2z. Since it's multiplcation, you have to divide by 2 to change it into a 11. And you always have to do the same thing to the other side of the equation. So, divide both sides by 2:
z = 1
Voila! z =1 is the SAME exact equation as the original.

2006-09-17 19:53:36 · answer #4 · answered by Anonymous · 0 0

2z+1 = z-z+3
2z= 4
z=2

2006-09-17 19:41:23 · answer #5 · answered by u e 2 · 0 0

1) 2z + 1 = z - [2z- z +3]
2) 2z = -2z + 2
3) z = -z + 1

Best guess...

2006-09-17 19:42:44 · answer #6 · answered by RHJ Cortez 4 · 0 0

2z+1=z-(2z-z-3)
2z+1=z-2z+z+3
2z+1=2z-2z+3
2z+1=3
2z=3-1
2z=2
z=1

2006-09-17 21:26:55 · answer #7 · answered by moosa 5 · 0 0

Trying to get other people to do your homework?

2006-09-17 19:39:20 · answer #8 · answered by i ♥ applesauce™ 2 · 0 0

figure it out

DO NOT TELL HIM THE ANSWER!!!!!!!!!!!!!!!!!

2006-09-17 19:41:56 · answer #9 · answered by coldman64 2 · 0 0

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