2006-09-17 12:01:49 · 6 answers · asked by ARELL D 1 in Science & Mathematics ➔ Mathematics
Several combinations. I will exclude 9 crayons of half and half or purple.
1 red - 8 blue
2 red - 7 blue
3 red - 6 blue
4 red - 5 blue
5 red - 4 blue
6 red - 3 blue
7 red - 2 blue
8 red - 1 blue
8 combinations possible. The zero and 9 are theoretical constructs only. You said that you "have" and this implies that you must possess at least one red and one blue crayon.
If your problem stated that you "have 9 crayons" and each must be red or blue, then the 0 and 9 combinations would be allowed and 10 combinations would be possible.
2006-09-17 12:04:07 · answer #1 · answered by Richard 7 · 71⤊ 0⤋
9
2006-09-17 12:03:49 · answer #2 · answered by Anonymous · 0⤊ 0⤋
0 red 9 blue
1 red 8 blue
2 red 7 blue
3 red 6 blue
4 red 5 blue
5 red 4 blue
6 red 3 blue
7 red 2 blue
8 red 1 blue
9 red 0 blue
(10 combinations)
2006-09-17 12:07:17 · answer #3 · answered by math geek 3 · 0⤊ 0⤋
9 of each. Each of them are red AND blue.
???
2006-09-17 12:03:11 · answer #4 · answered by Anonymous · 0⤊ 0⤋
81?
2006-09-17 12:09:14 · answer #5 · answered by Wilochka 4 · 0⤊ 0⤋
Depends on how many you can give me. But I guess... you have nothing as it belong to your friends... (smile)!!!
2006-09-17 12:04:32 · answer #6 · answered by wacky_racer 5 · 0⤊ 0⤋