how do i solve these?
first problem
2x+3y=3
4x+5y=5
second problem
x+2y=5
3x-15+-6y
2006-09-17 11:43:23 · 4 answers · asked by jgjhfw 1 in Education & Reference ➔ Homework Help
2x+3y=3
4x+5y=5
solve one of the problems for x
2x+3y=3
2x=3-3y
x=(3-3y)/2
now substitute for x in second equation
4x+5y=5
4[(3-3y)/2]+5y=5
2(3-3y)+5y=5
6-6y+5y=5
6-y=5
-y=-1
y=1
since y = 1
plug it into the first equation and solve for x
2x+3=3
x=0
i will leave it to u to do the second example. just use the same steps. hope this helped.
2006-09-17 11:58:47 · answer #1 · answered by Matty G 2 · 1⤊ 0⤋
To solve two variables in two equations find the LCM, lowest common multiple. 3times 5 is 15, 5 times 3 is 15 perfect.
Rewrite your equations accordingly
(2x + 3y)5 = 10x + 15y = 15
(4x + 5y)3 = 12x + 15y = 15
Now set it up like a subtraction problem.
12x + 15Y = 15
10x + 15 y = 15
_____________
2x + 0y = 0
simplify 2x =0
then just substitute the value for x into both equations to solve for y.
2006-09-17 18:59:37 · answer #2 · answered by Grev 4 · 0⤊ 0⤋
Solve for x or y then plug it in to find the second variable. Once you have the number for the second variable plug it in the get the first one.
This works for both problems.
2006-09-17 18:55:35 · answer #3 · answered by Nikki 1 · 0⤊ 0⤋
try using the disstributive property
2006-09-17 18:45:14 · answer #4 · answered by Bashek 2 · 0⤊ 0⤋