What is the length and width of a rectangle when you know that the perimeter is 86?
2006-09-17 11:26:41 · 18 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
I know that the answer can be anything, My daughter needs to show how to GET the answer
2006-09-17 11:28:30 · update #1
The teacher said that she could ask at home, but it has been so long since I have done math like this, that I am not sure. I dont need comments that say that you arent going to give homework answers!!!!!
The right answer gets 10 points
2006-09-17 11:31:21 · update #2
I will know the right answer tomorrow.
2006-09-17 11:37:58 · update #3
a good 3rd grade problem solving technique is guess and check
for example make the width 20 then then the lengh is 26
2006-09-17 11:42:39 · answer #1 · answered by Whoa!!Whoa!! 4 · 0⤊ 0⤋
All that needs to be true is that the length and width must add up to 43 (half the perimeter). So 20 and 23; 18 and 25, for example
2006-09-17 18:33:07 · answer #2 · answered by MollyMAM 6 · 0⤊ 0⤋
draw a rectangle to fiqure it out.label the perimeter=86,the longer side as length, as well as the side of the rectangle as width.put w+l=86 and 2(w) 2(l)=86. divide the width for the answer and the difference for length.
2006-09-17 19:03:37 · answer #3 · answered by christina p 4 · 0⤊ 0⤋
a rectangle? It could be anything!
For example it will have 2 sides of equal length and another two sides of equal length. So you could have one side at 10, the opp side will also have to be 10. This would leave the other 2 sides to 33 each.
You can't answer this question with a definate number because any number is possible
2006-09-17 18:30:02 · answer #4 · answered by Joe_Floggs 3 · 0⤊ 0⤋
By knowing the ratio properties of the rectangle;
*Length is two times its width... a sort of like that. and then 2 L + 2 W = 86(rectangular formula).
*Where if the ratio of the rectangle is (2L is equal to W...???just for illustration) and the rest is algebraic basic solution... by substituting the ratio, 2L + [(2L)(2L)] = 86.
*And by having L,... substitute L in the equation number 1(rectangular formula), and you'll get the W!
*Thereby you'll have the structural figures of the rectangle.
2006-09-17 18:44:05 · answer #5 · answered by wacky_racer 5 · 0⤊ 0⤋
The answer can't be "anything" but it can be many things. Start with two equal sides, say 30 and 30. The remaining two sides must be equal to 86-30-30=26, so each of the other two sides are 13 each (half of 26)
2006-09-17 18:31:43 · answer #6 · answered by Anonymous · 0⤊ 0⤋
43 is the width and the lenght is 2 because 43 x's 3 equals 86
2006-09-17 18:29:44 · answer #7 · answered by Anonymous · 0⤊ 1⤋
Let x and y be the adjacent sides. Then
perimeter P = 2x + 2y = 86
So x + y = 43
Then x can take any value greater than 0 and less than 43,
and y = 43 - x. There are infinitely many values for
x and y if x and y are real.
2006-09-17 19:56:28 · answer #8 · answered by steiner1745 7 · 0⤊ 0⤋
To calculate length, P, you need width, W, and length, L.
P = 2W + 2H
In this case, 86 = 2W + 2L, or
43 = W + L
That is, the lenght and width must sum to 43. Any combination that sums to 43 works.
2006-09-17 18:32:38 · answer #9 · answered by john977 2 · 1⤊ 0⤋
Like everyone else is saying, there are many possible solutions. Here is one of them: Side One = 23, Side Two = 23, Side Three = 20, Side Four = 20. (23, 23, 20, 20)
2006-09-17 18:42:42 · answer #10 · answered by math geek 3 · 0⤊ 0⤋