The sum of two numbers is 96. The second is 8 more than 3 times the first. What are the two numbers?

Answer 1

im not gonna answer this one for you, you should do your own HW, or maybe try to be more secretive about your actions. u didnt wait long enough between posts.

Answer 2

x=22 22 times 3= 66+8=74

74+22=96

Answer 3

We have to set up two equations for this... First, letting x be the first number and y being the second, x+y=96, and y=3x+8.
Now we solve the first equation for y, getting y=96-x
Substituting that for y in the second equation gives us 96-x=3x+8
Solving that gives us 4x=88, so x=22. Now plugging that into the first equation gives us 22+y=96, or y=74. So the first number is 22, the second number is 74.

Answer 4

the 2 numbers are 22 and 74

96 = x + (3x+8) =>
96 - 8 = x + 3x =>
88 = 4x =>

88 / 4 = x => x = 22

3(22) + 8 = 66 + 8 = 74

Answer 5

Let the first number be a and the second number be y.
x+y=96---(1)
x-8=3y---(2)
From (2), x-8=3y
x=3y+8---(3)
Sub(3) into (1)
3y+8+y=96
4y=88
y=22
Sub y=22 into(1)
x+22=96
x=84
So the first number is 84 and the second number is 22.

Answer 6

22 and 74

Answer 7

first you add 3 (number of times the first) and 1 (the first)
you get 4 - then you divide 96 by 4 to get what each one is
you get 24 - 24 is one number and 72 is other (24x3)
now we take the 8
divide 8 by two
you get4
add 4 to the bigger number, and subtract to the smaller number
24-4=20, 72+4=76
those are your two numbers!

Answer 8

3x+8+x=96
4x=88
x= 22 first number

and 3x+8 = 66+8= 74 second number

Answer 9

74 and 22

Answer 10

22 and 74

Answer 11

74