2006-09-17 10:06:04 · 11 answers · asked by suly m 1 in Education & Reference ➔ Homework Help
suppose one no is X and the other Y
then X+Y=34
X-Y=6
Add the 2 equations
2X=40
X=20
so y= 14
simple
2006-09-17 10:18:55 · answer #1 · answered by virgodoll 4 · 0⤊ 0⤋
14 and 20.
take 34/2 = 17
if the difference between the two numbers is 6, then you add 3 to 17 and subtract 3 from 17 (so that the diff b/n the numbers is 6, so 3 each way).
so 17 + 3 = 20
and 17 - 3 = 14
20 + 14 = 34!!!
2006-09-17 17:08:57 · answer #2 · answered by mighty_power7 7 · 1⤊ 0⤋
The two numbers are 20 and 14.
An easy way to find such an answer is to divide the number (34) by 2 (quotient is 17). Then divide the difference of the two numbers (6) by two (quotient is 3). Add the quotient to the first number you got (17+3+20), and then subtract the quotient from the first number (17-3=14). Add the two final numbers together to check your answer.
2006-09-17 17:09:01 · answer #3 · answered by : ) 4 · 0⤊ 0⤋
14 and 20
2006-09-17 17:07:49 · answer #4 · answered by Anonymous · 0⤊ 0⤋
20 and 14
2006-09-17 17:07:34 · answer #5 · answered by Anonymous · 1⤊ 0⤋
14 and 20
2006-09-17 17:08:21 · answer #6 · answered by samtomrob 2 · 0⤊ 1⤋
they are 20 and 14
2006-09-17 17:09:50 · answer #7 · answered by arammds2000 1 · 0⤊ 0⤋
14 + 20 = 34.
their difference is 6.
34=2x -6
40=2x
x=20
2006-09-17 17:09:55 · answer #8 · answered by avalentin911 2 · 0⤊ 0⤋
20 and 14
a+b=34
b=(a+6)
a+(a+6)=34
2a=34-6
2a=28
a=28/2
a=14
b=34-14
b=20
this is the most funny Q I ever answered
and this will be the most babish and detailed answer
2006-09-17 17:15:31 · answer #9 · answered by adorable 4 · 0⤊ 1⤋
14 and...20 i win
2006-09-17 17:08:39 · answer #10 · answered by Anonymous · 0⤊ 1⤋