English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

Ok, here it is: An electron is moving in a circular path around a long, uniformly charged wire carrying 2.5 nC/m. What is the electron's speed? Answer: 2.8 Mm/s. Please help me with the process.

2006-09-17 09:45:04 · 3 answers · asked by thomthum2000 2 in Science & Mathematics Physics

3 answers

The electric field of the wire is E=2l/r where l is the linear charge density (in electrostatic units). Set the force eE equal to the mass times the centripetal acceleration v^2/r to get:

v = sqrt(2*l*e/m)

l=.075 esu/cm , e = 4.8 x 10^(-10) esu , m = 9.1 x 10^(-28) g

-->

v = 2.8 x 10^8 cm/sec

2006-09-20 10:41:11 · answer #1 · answered by shimrod 4 · 0 0

What I think they want you to do is figure that the charge was induced by the electron. It has been a long time since I have had physics 2 but I here is what I think you need to do
1) Give all the information, I don't think that the question only had that little information
Start with cross-sectional area of the wire, then calculate the Electric field inside the wire. Maybe the temperature or material of the wire. There is more involved than just that, I am sure. That is assuming you know the charge of the electron. You can do this by yourself. Just look at all the information, then look at your formulas and start relating different formulas to each other. You'll get it

2006-09-18 10:00:45 · answer #2 · answered by jd2rivett 3 · 0 0

I assume you want to calculate an electron drift speed, but am confused by the information you give. You give a charge for the wire rather than a current. Don't see why a static charge in a circular loop has to move at all. Sorry.

2006-09-17 12:46:08 · answer #3 · answered by SAN 5 · 0 0

fedest.com, questions and answers