How much energy is used to lift a 1 lb object in the air (hovering)?

Question

So how much energy is required to lift a 1 lb object in the air?
And how does this relate to a 10 lb, 100 lb, and 1000 lb object?

Like if you were trying to make a flying car... i know sounds weird

ok so is that lifting the object 1 foot in the air or 1 inch?

Answer 1

energy=work done=force*dist/height
mass*gravitational acceleration*ht=1*32*1=32 ft lbs
for 10 lbs=320 ft lbs
fro 100 lbs 3200 ft lbs and so on

Answer 2

Don't believe rfamilymember - he forgot that the pound is not a unit of mass, it's weight or force.

If you lift a 1 lb object up 1 foot and hold it there, the work done and energy used is 1 lb*1 ft = 1 ft-lb = .001285 Btu. If the object weighs 10 , 100, or 1000 lbs, the energy used would be 10, 100, or 1000 times as much. If you lifted it only 1 inch it would be 1/12th as much.

Answer 3

When you say hovering, I assume you mean with no connection to the ground.
In this case, it would require a propellor or some jet device to provide the 1 lb upward force to oppose gravity.
This would require a continuous supply of energy, or power.
The amount would depend on the quantity of air being accelerated downwards, so a high speed jet would require much more power than a large helicopter rotor.
The power required is the mass of air per second times the downward velocity squared (its kinetic energy), divided by the efficiency of the system.
The whole thing is scaleable by weight and the mass per second of air, but air velocity must be kept constant and also the efficiency.
So, rotor or jet area must increase proportional to mass.

Your flying car would look a lot like a helicopter.

Answer 4

When you talk about "energy" it is not so simple, and depends on which type of thrust you are using.
Energy losses are not the same when you are using different type of engines.
Also, you must put time in analysis. It is not the same energy that you need for 1 minute flying and for 1 hour flying.

If you are talking about force, than the problem is very simple.

Hovering force = Weight of the body

Answer 5

It is a potential energy which the weight has in the air(hovering)so you will need the same energy to maintain at this place.

Ug=mgh

Answer 6

if a wonderfully effectual motor have been to enhance a 25N merchandise to a top of 1m, then the artwork finished could be = rigidity*distance = 25J. as your gadget required 45J to try this then 20 J of "greater potential" grew to become into necessary to end the comparable volume of artwork in authentic lifestyles, this inefficiency would desire to be from losses simply by warmth, friction, viscosity, and so on. in case you're to anticipate that the sole loss mechanism is warmth production, then 20J grew to alter into warmth. cheers