2006-09-17 07:22:02 · 11 answers · asked by snook 1 in Science & Mathematics ➔ Mathematics
2(y+1)-5=7
2(y+1)=7+5
2(y+1)=12
2(y+1)/2=12/2
y+1=6
y=6-1
y=5
2006-09-17 07:28:35 · answer #1 · answered by Anonymous · 1⤊ 0⤋
y=5
2006-09-17 14:30:01 · answer #2 · answered by POPPY 5 · 0⤊ 0⤋
y=5
2006-09-17 14:29:50 · answer #3 · answered by Mr. Truknit 4 · 0⤊ 0⤋
2 (y+1)-5=7
2y=2-5=7
2y-3=7
2y=10 ===>
y=5
2006-09-17 14:25:39 · answer #4 · answered by alireza w 1 · 0⤊ 0⤋
2y + 2 -5 = 7
2y -3 =7
2y = 7 +3
y= 10 / 2
y = 5
2006-09-17 14:29:57 · answer #5 · answered by Anonymous · 0⤊ 0⤋
2(y+1)-5 =7
2y+2-5=7
2y + - 3 =7
2y - -3 =7 +3
2y= 10
y =5
2006-09-17 14:30:35 · answer #6 · answered by bi_cali_chick86 2 · 0⤊ 0⤋
2(y+1)-5 =7
2y+2-5=7
2y + - 3 =7
2y - -3 =7 +3
2y= 10
y =5
2006-09-17 14:25:11 · answer #7 · answered by C 2 · 0⤊ 0⤋
2(y + 1) - 5 = 7
2(y + 1) = 12
y + 1 = 6
y = 5
2006-09-17 14:35:28 · answer #8 · answered by Sherman81 6 · 0⤊ 0⤋
2y + 2 - 5= 7
2y - 3 = 7
2y= 10
y= 5
2006-09-17 14:32:12 · answer #9 · answered by Trish 2 · 0⤊ 0⤋
the answer is 5
2006-09-17 14:27:29 · answer #10 · answered by bo_cloe 1 · 0⤊ 0⤋