how can i calculate the mass of 3.78 moles of sulfur trioxide?
2006-09-17 07:20:37 · 6 answers · asked by Simply Me 5 in Science & Mathematics ➔ Chemistry
First calculate how much one mole of sulfur trioxide would weigh. This will be the sum of all the atomic weights: 1 sulfur + 3 oxygens. Now multiply that number by 3.78 and you will have your answer.
32.06 + 3 (16.00) = 80.06.
The mass of 3.78 moles is 3.78 (80.06) = 303 g
It is important to note that your question was asked with 3 significant figures. You can carry one extra digit through the calculations, but your answer should be rounded to 3 significant figures to match the data in your question. You can't have an answer that is more "precise" than the least precise information that went into it. (note that the 3 is exact, really 3.00000000).
Aloha
2006-09-17 07:28:54 · answer #1 · answered by Anonymous · 2⤊ 0⤋
Figure out the atomic mass of sulfur trioxide and then multiply this number by 3.78 to get grams the mass in grams.
2006-09-17 07:24:44 · answer #2 · answered by bruinfan 7 · 0⤊ 0⤋
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2016-05-16 04:00:11 · answer #3 · answered by Anonymous · 0⤊ 0⤋
find the mass of one mole of SO3:
one sulfur 32.07
three oxygens each 16.00x3=48.00
80.07 g/mole
multiply by 3.78 moles=302.66 grams
2006-09-17 07:24:45 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Sulfur Trioxide is SO3. The atomic mass of sulfur is 32.060 and Oxygen is 15.999. So one mole is 32.060 + 3(15.999) = 80.058.
3.78 moles is 3.78(80.058) = 302.619g
2006-09-17 07:23:49 · answer #5 · answered by Anonymous · 0⤊ 0⤋
I don't know. But do your own homework
2006-09-17 07:21:43 · answer #6 · answered by ☼shine☼ 3 · 0⤊ 0⤋