2006-09-17 05:54:37 · 6 answers · asked by jilljeter2004 1 in Science & Mathematics ➔ Mathematics
You must have a typo somewhere.
The derivative of 17 (or any other constant) is ZERO.
Are you sure there aren't some x variables in your f(x) function that you are supposed to find the derivative of?
2006-09-17 06:12:27 · answer #1 · answered by I ♥ AUG 6 · 0⤊ 0⤋
If f(x) = c where c is any real number, then the derivative
f'(x) = 0. In particular when c = 17, the derivative of f(x) = 17 is 0.
2006-09-17 13:30:17 · answer #2 · answered by Gypsy Catcher 3 · 0⤊ 0⤋
f(x)=17
derivative of the funcion f(x)=f '(x)
= limit f(x+h)-f(x)/h
h tends to 0
= limit f(x+h)-17/h
h tends to 0
= limit (17-17) / h
h tends to 0
= limit 0 / h
h tends to 0
= limit 0
h tends to 0
=0.
The derivative of a constant function is zero.
2006-09-17 13:14:06 · answer #3 · answered by Anonymous · 0⤊ 0⤋
I think by derivative you mean df(x)/dx i.e. derivative of the function w.r.t X.
Anyway, the answer is 0.
2006-09-17 12:58:50 · answer #4 · answered by Anand 2 · 0⤊ 0⤋
Suppose f(x) = c
f'(x) = lim h->0 [f(x+h)-f(x)]/h
= lim h->0 [(c-c)/h] = lim h->0 [0] = 0
The derivative of any constant function is 0.
2006-09-17 13:02:03 · answer #5 · answered by Andy S 6 · 0⤊ 0⤋
it is zero.
A constant as a function has no change over the real numbers, therefore the rate of change (whether at a point or not) is zero.
2006-09-17 12:59:33 · answer #6 · answered by Anonymous · 0⤊ 0⤋