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V=(8 V/m^4) (x^2) (y^2) + (3.9 V/m^4) (z^2) (x^2 - 6 m^2) + (6.6 V/m^4) (y^3) (z)

considering (x, y, z):

What is the y component of the electric field at (1.7m, -4m, 6.6m)? Answer in units of V/m.

Any help would be greatly appreciated, keep in mind that the above equation is equal to the potential, not the E field

2006-09-17 05:29:49 · 2 answers · asked by to the beat in my head 3 in Science & Mathematics Physics

I was able to get the answer following the advice of the first answerer. thank you very much for your help.

to the second comment: the meters will cancel out in the end

2006-09-17 08:23:55 · update #1

2 answers

if I remember correctly, (it's been some time), the relation between electric potential (V) and electric Field (E) is

E = - dV/dx

so if you want the y component of th electric field, differentiate that expression with respect to y and negate it.

E(y) = -dV/dy

and substitute values x,y and z to get the y component of the electric field at that point.

Can you take it from here? or do you want me to work out the arithmetic too? :p

2006-09-17 05:54:25 · answer #1 · answered by Ra.Ge 3 · 0 0

I'm confused. Electric potential is measured in volts not v/m^4.
One of your terms even has an m^2 in it.

2006-09-17 15:13:05 · answer #2 · answered by Demiurge42 7 · 0 0

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