I need help on solving these problems. square root of (y+15) - square root of (2y+7) = 1?

Answer 1

Square the left and right side.
Expand out the equation and solve.
Let ( y + 15)^0.5 - ( 2y +7)^0.5 = 1 be equation 1

From equation 1. You bring the root of (2y+7) to the right side, square both sides and you get

y+ 15 = 2y + 7 + 1 + 2( 2 y+ 7)^ 0.5 ----Equation 2

Bring the non-rooted terms over to the Left hand side to get

15 - 8 + y - 2y = 2 ( 2y + 7)^0.5
7 - y = 2 ( 2y + 7 )^0.5

Squaring both sides:
49 - 14 y + y^2 = 4 ( 2 y + 7 )

Bring over the right hand side to the left side to get

y^2 - 22 y + 21 =0
( y - 21 )( y - 1) = o

y = 21 or y = 1

Answer 2

send one of the terms to the other side
square root of (y+15) = 1 - square root of (2Y+7)
square both sides,
then keep only one square root on one side and the rest on the other side
then square it again

Answer 3

square both sides.
now remember that (a-b)squared is (a)squared + (b)squared - 2ab

so y+15 + 2y + 7 - 2 (y+15)(2y+7) = 1
3y + 22 -2(2ysqr +22y + 7*15) = 1
-4ysqr -41y -188 = 1
4ysqr +41y +189 = 0

solve this regular quadratic equation to get two values for y

Answer 4

do u mean sqr(y+15) - sqr(2y+7) = 1
sqr(y+15) = 1 + sqr(2y+7)
y+15 = 1 + 2sqr(2y+7) + 2y+7
15 - 1 -7 = 2sqr(2y+7) +2y - y
7 = 2sqr(2y+7) + y
7 - y = 2sqr(2y+7)
49 - 14y + y^2 = 4(2y + 7)
y^2 -14y + 49 = 8y +28
y^2 - 22y + 21 = 0
now solve for y

Answer 5

undecided approximately algebra - long term provided that i grew to become into in college - sixty six years in the past. What you do to one fringe of the equation you're able to do to the different, so 2?(x+2)-3 = 7 upload 3 to the two side 2?(x+2) =10 divide the two facets by making use of two ?(x+2) = 5 sq. the two side x+2 = 25 subtract 2 from the two side x = 23 Now try the comparable with the different one - i'm getting the answer to be x = a hundred and five,468.5, which looks a wierd parent, yet i wish that is mind-blowing - you are attempting it and notice what you will get.

Answer 6

sqrt(y + 15) - sqrt(2y + 7) = 1
sqrt(y + 15) = sqrt(2y + 7) + 1

square both sides

(sqrt(y + 15))^2 = (sqrt(2y + 7) + 1)^2

y + 15 = (sqrt(2y + 7) + 1)(sqrt(2y + 7) + 1)
y + 15 = (2y + 7) + sqrt(2y + 7) + sqrt(2y + 7) + 1
y + 15 = 2y + 7 + 2sqrt(2y + 7) + 1
y + 15 = 2y + 8 + 2sqrt(2y + 7)
-y + 7 = 2sqrt(2y + 7)

same as

7 - y = sqrt(4(2y + 7))

square both sides

(7 - y)^2 = 4(2y + 7)
(7 - y)(7 - y) = 8y + 28
49 - 7y - 7y + y^2 = 8y + 28
y^2 - 14y + 49 = 8y + 28
y^2 - 22y + 21 = 0
(y - 21)(y - 1) = 0

y = 1 or 21

Answer 7

first find out what y is.....(2y + 7) = 1.....once you find that then do (y+15) ..then do the square roots for both equations and then minus them and youll get ur answer

Answer 8

square both sides to find y and then you can solve!