Find the slope and y-intercept for the line y = 2x?

Answer 1

To find the y intercept, let x=0

Therefore, y = 2*0
y = 0

The slope of the line is equal to the rise (y2-y1) over the run (x2-x1)

Find two points on the line
Let x=0, y=0
Let x=1, y=2

x1 = 0
x2 = 0
x2-x1 = 1

y1= 0
y2=2
y2-y1=2

There for the slope is 2/1 = 2

(However, in the case of a linear equation of the example y = ax + b, a = the slope)

Answer 2

The slope is 2 and the y intercept is 0.

Answer 3

The general equation for a straight line in terms of its slope (m) & y-intercept (c)

is y = mx + c

Here the given equation of the straightline is

y= 2x.

This is virtually a st. line parallel to Y-axis. It won't cut the Y-axis.

So, the y-intercept is 0

The slope from the equation y= (slope) x
is 2.

Answer:.

Slope = 2; Y-intercept = 0 ....

Answer 4

because the standard form for this problem is y=mx+b where m is a real number and the slope and b is a real number and the y intercept point, you can easily find that 2 over 1 is the slope and because there is not b, or b is zero, there is no y intercept for this problem

Answer 5

Your equation is given in the form of "y = m*x +b," where "m" is the slope and "b" is the y-intercept. So

"m" or slope = 2
&
"b" or y-intercept = 0

Answer 6

y=2x
its in the form y=mx so the slope is coefficient of x ie 2;

(or more advanced dy/dx = 2)

y-intercept is the root for x = 0 so y = 2*0 = 0 and answer is 0;