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A, B, C are collinear with coordinates a, b, c respectively. If b= -10, c= 4 and |AB|= 28, find |BC| and |AC|. how many answers are possible?

2006-09-17 02:25:41 · 4 answers · asked by haler 1 in Science & Mathematics Mathematics

4 answers

well dear It's the formula you can use ;
|AB| = √(A^2 + B^2)
|AC| = √(A^2 + C^2)
|BC| = √(B^2 + C^2)
b = -10 , c = 4 , |AB| = 28

Step One;
|BC| = √(B^2 + C^2) = √(-10^2 + 4^2) = √100+16 = √116

Step Two;
we need to find 'a' first then |AC|;

|AB| = 28
|AB| = √(A^2 + B^2)
28 = √(A^2 + (-10)^2)
(28)^2 = [√(A^2 + (-10)^2)]^2
784 = A^2 + 100
A^2 = 784 - 100 ; A^2 = 684 , a = √684 = 26.15 as b = -10 & c = 4 its not possible.;

Step Three;
|AC| = √(A^2 + C^2) = √(684 + 16 )= √700

The final result is ;
|BC| = √116
|AC| = √700

Good Luck.

2006-09-17 03:13:00 · answer #1 · answered by sweetie 5 · 1 0

No, sorry "futbol_freak", the answer is not 5, it is 2.

If b=-10 and c=4 and the distance between A and B is 28, then A cannot be between B and C; there would not be enough space between A and C. The coordinates of A have to be either -38 or 18 to be 28 away from B. Therefore, there are only 2 answers.

2006-09-17 09:49:26 · answer #2 · answered by MDMMD 3 · 0 0

5

2006-09-17 09:32:52 · answer #3 · answered by (^_^) 5 · 0 0

Only one. You are too stupid to be in that class.

2006-09-17 09:32:49 · answer #4 · answered by Anonymous · 0 2

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