If you watch Mythbusters on Discovery Channel tonight at 9, you may just find out.
I've enjoyed watching them blow things up, etc for a while now.
The new series starts tonight with the write-up 'Can celebratory gunfire kill when the bullet falls back to earth.' I think this will answer your question.
2006-09-17 01:17:24
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answer #1
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answered by Treat Infamy 4
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That depends on how fast the bullet is to start with.
High velocity bullets (350 m/s) would go up to about 5 or 6 km before falling back. How fast will they fall? That depends on the angle. If the bullet was fired vertically, it will tumble and fall sideways, at a speed of perhaps 30 m/s (its terminal velocity). If it was fired at an angle, then the bullet will remain pointed end front, and will fall back almost as fast as it went up (slowed down only by air friction) and could be lethal.
The Mythbusters tried that on their show, with conclusive results.
2006-09-17 01:20:46
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answer #2
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answered by Vincent G 7
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Well, just for an example, during the Second World War both the British and German aerial defences fired "anti-aircraft" bullets at planes flying at over 20,000 feet - there were no planes which could fly high enough to be safe from them. So the bullets must still have being going fast enough to do some damage, even after 4 miles. Nobody was ever reported to have been hurt by the ones which missed, and there must have been millions of them.
2006-09-17 03:52:38
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answer #3
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answered by bh8153 7
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The distance will depend on the mass of the bullet, the caliber, and the volume of gas compressed in the chamber of the gun. Once it reaches its maximum point of travel,it will free fall back to earth at the rate of "32 ft. per second, squared" - the small fraction allowed for the friction created by the bullet passing through the molecules which create the atmosphere.
2006-09-17 01:17:25
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answer #4
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answered by thebushman 4
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Depending on the speed with which the bullet is released, we can determine the height that it will reach based on the formula:
v^2 = u^2 + 2as
where
v = final velocity = 0 m/s
u = initial velocity or bullet release speed
a = gravitational acceleration = -9.81 m/s2
s = displacement or height reached
As for the speed of it coming down, use the same formula of
v^2 = u^2 + 2as
but this time, the values are:
v = final velocity
u = initial velocity or velocity at the top = 0 m/s
a = gravitational acceleration = 9.81 m/s2
s = displacement or height reached
2006-09-17 08:29:27
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answer #5
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answered by Kemmy 6
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The distance it travels depends on the initial velocity .. if initial velocity of bullet be 'V' then it will reach 1/2((square of V) / g) , wher e 'g' is accelaration due to gravity .
and the speed it will come down to earth is the same as its initial velocity 'V'
2006-09-17 01:36:11
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answer #6
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answered by Biswajit S 1
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Hi. Depends on the muzzle velocity, but the effect of gravity will slow the bullet at 32 feet per second for each second of it's accent. (This is over 9 meters per second for each second.) The bullet will strike the ground at it's free-fall terminal velocity.
2006-09-17 01:15:39
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answer #7
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answered by Cirric 7
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What kind of gun? What calibre bullet? What's the weather like and what's your altitude to begin with? Do you really mean "what speed will it come down to earth at? " or "At what speed does it hit the ground?"
Short answers, "A long way" and "fast"
2006-09-17 01:17:04
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answer #8
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answered by NEIL M 1
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Why do you want to waste bullet up into the sky ? Don't you have something better?
2006-09-17 01:22:21
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answer #9
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answered by Anonymous
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It depends of the muzzle velocity of the weapon. If we ignore air resistance it will come down at the same speed as it went up.
I
2006-09-20 02:31:56
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answer #10
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answered by Mark G 7
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