25y²+4=0 can anyone solve this for me
2006-09-17 00:18:14 · 8 answers · asked by Anonymous in Education & Reference ➔ Homework Help
y = -0.40
2006-09-17 01:49:10 · answer #1 · answered by Anonymous · 0⤊ 0⤋
y^2=4/25
y=2/5
2006-09-17 00:28:22 · answer #2 · answered by tonima 4 · 0⤊ 0⤋
ok, that's a tough one, but let me try this:
we know how to get to zero from 4. we just subtract.
so that means that 25y squared = -4.
we don't know what y is so go for the cube of it.
the cube is 5y. so what times 5 is -4?
wait a minute. i'm thinking. don't have a calculator so i'm guessing about -.75.
does that work? i don't know. try it. it's close anyway.
2006-09-17 00:34:14 · answer #3 · answered by mrbobinkorea 2 · 0⤊ 0⤋
25y2+4=0
25y2=-4
y2= -4/25
y= +or- the square root of(-4/25)
y= +or-2/5i
2006-09-17 00:23:00 · answer #4 · answered by i Yh0rz 2 · 0⤊ 0⤋
Divide both sides by 25. Then take 4 away from both sides and then find the square root of y and the sum.
2006-09-17 00:19:16 · answer #5 · answered by goldfish65398 2 · 0⤊ 0⤋
y²= -4/25 = (i² * 4)/25 = + i (2/5) or - i (2/5)
2006-09-17 00:21:53 · answer #6 · answered by George 3 · 0⤊ 0⤋
maybe the problem is wrong , or you can't solve that in the real numbers multitude, perfect square number is always positive but here square y is negative 4 divided to 25 ,and you can't determine the square root
2006-09-17 00:23:19 · answer #7 · answered by Strange Ball 2 · 0⤊ 0⤋
y^2= - 4/25
which is impossible.
2006-09-17 01:17:57 · answer #8 · answered by 123321m 3 · 0⤊ 0⤋