a boy standing on the ground 20.0 m from a building throws a snowball into a window 15.0 m above the ground so that it enters the window horizontally. find the initial velocity of the ball (speed and direction)
2006-09-16 22:30:49 · 3 answers · asked by Anonymous in Education & Reference ➔ Homework Help
Here,
v=0m/s [ball stopped vertical displacement after reaching the top]
s=(20^2+15^2)^1/2=25m
a=g=-9.8m/s^2
u=?
Hence, by 3rd K.E
v^2=u^2+2as
0=u^2-2*9.8*25
0=u^2-490
u=22.135m/s at about 37 degrees(approx.)
sorry for any inconvenience in reading the answer, its due to the limitations of my device.
||Good Luck||
2006-09-16 23:20:00 · answer #1 · answered by Cephalic 3 · 0⤊ 0⤋
It is not possbile to enter the building horizontally, the snowball must be at some angle.
2006-09-16 22:39:58 · answer #2 · answered by Froggbitz 2 · 0⤊ 0⤋
The time needs to be mentioned.
2006-09-16 23:04:33 · answer #3 · answered by labyrinth 3 · 0⤊ 0⤋