Use order of operation
2x- 3 [2x-4y -x + y - 3] + 7 (multiply within the parenthesis)
2x - 3 [x - 3y -3] + 7 (Combine like terms in parenthesis)
ok now you do the rest - just kidding
2x -3x + 9y + 9 + 7 (Multiply the -3 to everything inside the parenthesis)
-x + 9y +16 (Combine like terms)
2006-09-16 21:43:41
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answer #1
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answered by Miss. Tee98 4
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2x - 3 [ 2 (x - 2y) - (x - y) - 3] + 7
= 2x - 3[ 2x - 4y - x + y - 3] + 7
= 2x - 6x +12y +3x - 3y + 9 + 7
= 2x - 6x + 3x + 12y - 3y + 9 + 7
= -x + 9y +16
hence
2x - 3 [ 2 (x - 2y) - (x - y) - 3] + 7 = -x + 9y +16
or
2x - 3 [ 2 (x - 2y) - (x - y) - 3] + 7 = 9y - x +16
2006-09-17 04:48:33
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answer #2
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answered by rav142857 4
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2x - 3 [ 2 (x - 2y) - (x - y) - 3] + 7
= 2x - 3( 2x-4y - x+y -3 ) + 7
= 2x - 3(x - 3y -3 ) +7
= 2x - 3x + 3(3y) + 9 +7
= -x + 9y + 16
2006-09-17 06:06:02
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answer #3
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answered by mahesh 1
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2x - 3(2x - 4y - x + y - 3) + 7 =
2x - 6x + 12y + 3x - 3y + 9 + 7 =
-x + 9y + 16
2006-09-17 04:46:01
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answer #4
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answered by Forest_aude 3
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2x - 3 [ 2 ( x - 2y ) - ( x - y ) - 3 ] + 7
2x - 3 [ 2x - 4y - x + y - 3 ] + 7
2x - 3 [ x - 3y - 3 ] + 7
2x - 3x + 9y + 9 + 7
= - x + 9y + 16
2006-09-17 06:28:51
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answer #5
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answered by crestfallen 5
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Use the order of operations:
parantheses, then multiplication/division, then addition/subtraction, working left to right.
So:
2x-3[2(x-2y)-(x-y)-3]+7
becomes:
2x-6(x-2y)-3(x-y)-9+7
becomes:
2x-6x+12y-3x+3y-2
Collecting like-terms:
-7x+15y-2
2006-09-17 05:27:23
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answer #6
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answered by benmaloney 2
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=2x-3[2x-4y-x+y-3]+7
=2x-3(x-3y-3)+7
=2x-3x+9y+9+7
=-x+9y+16
2006-09-17 06:53:36
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answer #7
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answered by Anonymous
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9y-x+16
2006-09-17 04:40:08
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answer #8
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answered by Pedro I. Wong 3
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2x-3[2x-4y-x+y-3]+7
2x-6x+12y+3x+9-3y+7
9y-x+16
2006-09-17 06:46:40
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answer #9
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answered by CHIMPU 2
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2x-3[2x-4y-x+y-3]+7
2x-3(x-3y)+7
2x-3x+9y+7
-x-9y+7
2006-09-17 04:47:25
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answer #10
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answered by SkkARd 3
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