A 29.9 ml sample of a solution of RbOH is neutralized by 22.56 ml of a 1.499 M solution of HBr. What is the molarity of the RbOH solution?
2006-09-16 20:19:39 · 6 answers · asked by SphinxEyez999 2 in Science & Mathematics ➔ Chemistry
RbOH + HBr --> RbBr +H2O
no. of moles of HBr = (22.56/1000) x 1.499 = 0.033817mol
mole ratio = RbOH:HBr
no. of mole of RbOH = 0.033817mol
Molarity of RbOH = 0.033817/(29.9/1000) = 1.13M (Ans)
2006-09-16 22:30:22 · answer #1 · answered by siangal07 2 · 0⤊ 0⤋
i dont know, but i'd say you would firstly need to find out 22.56 ml of a 1.499 M.
2006-09-16 20:24:20 · answer #2 · answered by kristyb872001 6 · 0⤊ 0⤋
Uh, brain freeze!
2006-09-16 20:26:37 · answer #3 · answered by matthewoborne 2 · 0⤊ 0⤋
If you know the answer OK and if you don't know you have to see it in calculator or in calculator of your computer because I don't know the answer.
2006-09-16 20:24:06 · answer #4 · answered by Red Alert 1 · 0⤊ 0⤋
M1/V1 = M2/V2
M1*V2/M1 = M2
(1.499M)*(29.9mL)/(22.56mL) = M2
1.987 = M2
2006-09-16 20:25:15 · answer #5 · answered by sft2hrdtco 4 · 0⤊ 0⤋
use M1V1=M2V2 eqn
2006-09-17 00:11:10 · answer #6 · answered by CHIMPU 2 · 0⤊ 0⤋