Could I get help with these two problems, please?

Question

((x/7-1/2)=(x-11/2))

((6/3x-2)+(3/2x))

Thanks!

Answer 1

((x/7-1/2)=(x-11/2))--Solve for x?

(2x-7)/14=(2x-11)/2
(2x-7)/7=(2x-11)
2x-7=14x-77
-12x=-70
x=35/6

((6/3x-2)+(3/2x))---Simplify?

(6-6x)/3x + 3/2x
(12x-12x^2+9x)/6x
(-4x+7)/2

Answer 2

the first problem, (x/7-1/2)=(x-11/2), is an equation. Therefore you need to get the x terms on one side and the constants on the other. First off, the parenthesis are redundant, so they can be removed: x/7-1/2=x-11/2. Now to bring the terms together: x/7-x=-11/2+1/2. get the LCD of x/7 and x: x/7-7x/7=-11/2+1/2. Combine like terms: -6x/7=-10/2. Cross multiply: -12x=-70. Divide both sides by -12: x=-70/-12. Simplify to get the final answer: x=35/6.

The second problem (6/3x-2)+(3/2x) is not an equation; all you do is simplify. Again, the parenthesis are redundant, so you have 6/3x-2+3/2x. Bring like terms together 6/3x+3/2x-2. Get the LCD of 6/3x+3/2x: 12/6x+9/6x-2. Add the x terms together for the final answer: 21/6x-2.

Answer 3

the lcd of 7,2,2 is 14. multiply both the sides by 14.


14 (x/7 -1/2) = 14 ( x -3/2 )
2x- 7 = 14x - 21
21 - 7 = 14x -2x
14 = 12x
x = 14/12 =7/6 =1 1/6

what do you want to do to the next exprsn?

Answer 4

I see why you re-wrote it and posted it again. In the first version, each was preceded by a question number and a hyphen . . . which was easily misinterpreted as a number and a minus sign as part of the question!

I might suggest re-writing yet again with more parentheses, clarifying what's in each numerator and what's in each denominator. (See my answer to the first version of the question.) Also, you don't need the far left and far right parentheses on each line; they aren't grouping anything to separate it from anything else; it just clutters the line.

Answer 5

Your question is incomplete. It is vague in the sense what is required to be done!