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I am really horrible at Math. Could I get some help? Complex fractions
((m^3/7)/(m^7/28))
I came up with 4^4.
Did anyone else?

2006-09-16 16:30:41 · 8 answers · asked by Anonymous in Science & Mathematics Mathematics

8 answers

Where did your m go? It should still be there.
(m^3/7)/(m^7/28)
= (m^3/7)(28/m^7)
= 4/m^4

2006-09-16 16:33:48 · answer #1 · answered by MsMath 7 · 3 1

m^3/7 times m^7/28 is m^19/28 because when you multiply by like bases, you add the exponents. four to the fourth could be right depending on your m value.

2006-09-16 23:34:24 · answer #2 · answered by bsbllplayr216 3 · 1 0

((m^3/7)/(m^7/28))

= m^ (3/7 - 7/28)
= m^ (12/28 - 7/28)
= m^ (5/28)

2006-09-17 03:46:13 · answer #3 · answered by b0b0link 2 · 1 0

((m^3/7)/(m^7/28))

= m^ (3/7 - 7/28)
= m^ (12/28 - 7/28)
= m^ (5/28)

2006-09-16 23:40:10 · answer #4 · answered by Nirmal87 2 · 1 0

ya you messed up good m^(5/28)
I am 100% certain.
when you divide exponents you substract (when you multiply you add) (3/7)/(7/28) (12/28)-(7/28) = 5/28 m^(5/28)
dunno what the person above me is saying :(

2006-09-16 23:35:22 · answer #5 · answered by RichUnclePennybags 4 · 1 0

Okay, an easy way to remember the rules is

MADSPM: Pronounced "Mad Spam"

MA
If you are "M" ultiplying then you need to "A"dd the Exponents

DS
If you are "D"ividing then you need to "S"ubtract the Exponents

PM
If you have "P"arenthesis then you need to "M"ultiply the exponents
(ex: (x ^ a)^b = x ^(a*b)

2006-09-16 23:45:59 · answer #6 · answered by Farrah 2 · 1 0

type in math or some type of math in the search box and you will find all kinds of math help for free. good luck

2006-09-16 23:34:17 · answer #7 · answered by rainydaydreamr 4 · 1 1

What is m? Depends on the value of m

2006-09-16 23:34:10 · answer #8 · answered by A 4 · 1 0

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