English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

our science class made one with tin cans, candle, ater to see how much heat was absorbed by the water.
Would the heat of combustion be calculated higher or lower from a real calorimeter?

2006-09-16 12:50:32 · 2 answers · asked by sungirl 2 in Science & Mathematics Chemistry

2 answers

Higher.

The bomb calorimeter is built to catch essentially all of the heat from the burn. The bucket water around the bomb is circulated continuously. The bomb has it's weight factored in. There is a computer which waits for the change in water temperature to level out. Around the bucket, there is an air layer, around that within the calorimeter walls, water is circulated to hold the temperature around the bucket stable.

The machine I worked with for years was an industrial model. It was important to capture all the heat of combustion because that determined the cost & final disposition of the materials we were testing.

I applaud your experiment & hope that you learned & had fun!

;-)

2006-09-16 14:11:36 · answer #1 · answered by WikiJo 6 · 0 0

i will not say. frequently, the time period "heating value" has a common frame of mind to calculation. Fuels have "heating value" that are inherent to the fuels, that are defined in accordance to effortless criteria. i anticipate it really is what's being suggested. As to the context-appropriate questions, i might want to easily bypass an interpretation with finished context. i trust that what's being finished the following is that there's a defined capacity output from some kit it fairly relies at using a gas having a given heating value. you would possibly want to be expected to have a more effective capacity output in case you've been to apply a gas with a more effective heating value, so that you may not get round the requirement by employing in basic terms substituting a more effective heating value gas. it fairly is, you may not attain the objective by employing replacing the gas. The performance of the unit might want to satisfy the defined requirement even as employing the defined gas, and in case you do not use a gas of that effortless heating value, you would possibly want to regulate the output objective to replicate that regulate.

2016-11-27 19:25:19 · answer #2 · answered by ? 4 · 0 0

fedest.com, questions and answers