what does a graph with celcius and fahrenheit temp.s plotted on it reveal about the relationship between F & C

Answer 1

one is great than the other but both the same....simple

Answer 2

There are 100 degrees between the boiling and freezing point of water in the Celcius scale. 0 C and 100 C . In the Fahrenheit scale there is 180 degrees between the boiling and freezing points of water. 32 F and 212 F Therefore Celcius degrees are bigger than Fahrenheit degrees.

Answer 3

Since C = 1.8F + 32, a plot would give a straight line of the form y - mx + b, where m is the slope and b is the x-intercept (that is, where y = 0). In this case, the slope is 1.8 and the intercept is 32, that is when C is 0, F is 32. Thus, C and F are linearly related.

Answer 4

The relationship will be that fahrenheit is atleast 60 degrees ahead of celcius in every situation.

Answer 5

since 100C and 212F both represent the boiling point of water, and 0C and 32F represent the freezing point of water, you can substitute both values into the linear relationship y = mx + b where y=Tf and x=Tc, and they yield Tf = 9/5Tc +32. you can then plot the relationship yourself. It is interesting to note that Tf = Tc at -40 degrees, so when it's 40 below it doesn't matter what scale you use - and it's really cold

Answer 6

Any degree to any degree

T1 (in unit A) - T2 (in unit A) T1 (in unit B) - T2 (in unit B)
------------------------------... = ------------------------------...
T (in unit A) - T1 (in unit A) T (in unit B) - T1 (in unit B)

where T are the tempratures to be converted and T1 and T2 are fixed tempratures as boiling and freezing points of water or any other feasible 'fixed' tempratues for reference

Theres a gap which is not showing properly

So heres another way to write same thing

((T1(A)-T2(A) ) / (T(A) - T1(A))) = ((T1(B)-T2(B) ) / (T(B) - T1(B)))

Answer 7

That the relation is linear of the type y = a*y+b

Answer 8

They're both linear. F = (C*1.8) + 32.

Answer 9

that they are different