The perimeter of a triangle is 76 cm. Side a of the triangle is twice as long as side b. Side c is 1cm longer than side a. Find the length of each side?
2006-09-16 10:09:42 · 8 answers · asked by Niecy C 1 in Education & Reference ➔ Homework Help
Break everything down in terms of the shortest side
a +b +c = 76
a=2b
c=2b+1
2b + b + 2b +1 = 76
5b = 76 - 1
5b = 75
b=75/5
b=15
Therefore side a = 2b, or 30cm
side b = 15cm
and side c = 2b + 1 = 31 cm
15 + 30 + 31 = 76
2006-09-16 10:19:02 · answer #1 · answered by cyrenaica 6 · 2⤊ 0⤋
Lets name x side a
then side a will be x/2
and side c will be (x+1)
so x +x/2 +(x+1)=76
2x+x/2=75
5x=150
x=30 so side a=30
b=15
c=31
I would appreciate your 10 points for my help
2006-09-16 10:22:29 · answer #2 · answered by girl24gr 3 · 0⤊ 0⤋
This is how i figured the problem.Side A=30 centimeters.Side B=15 centimeters.Side C=31 centimeters.30+15+31=76 centimeters.I hope this helps you.Oh by the way I really love math and am really good at math so you can always ask me for help.
2006-09-16 10:31:55 · answer #3 · answered by debralizjr 4 · 0⤊ 0⤋
side a = a
side b = a/2
sice c = a +1
a+b+c = 5*a/2 + 1= 76
5*a /2 = 75.
a = 30
b = 15
c = 31
2006-09-16 10:21:39 · answer #4 · answered by Dr GH 2 · 2⤊ 0⤋
Let x = length of side b
then
2x = length of side a
2x+1 = length of side c
x + 2x + 2x + 1 = 76
5x + 1 = 76
5x = 75
x = 15
so:
b= 15cm
a=30cm
c=31cm
2006-09-16 10:21:35 · answer #5 · answered by helpful guy 2 · 2⤊ 0⤋
a+b+c=76
a=2b
c=a+1
so
(2b)+b+(a+1)=76
or
(2b)+b+((2b)+1)=76
hence
5b+1=76
so
5b=75 or b=15
since a=2b, a=30 and since c=a+1, c=31
2006-09-16 10:21:39 · answer #6 · answered by nospamcwt 5 · 0⤊ 0⤋
31cm c
30cm a
15cm b
2006-09-16 10:20:06 · answer #7 · answered by Anonymous · 0⤊ 1⤋
Ask Mathgirl826. I hear she is real smart.
2006-09-16 10:19:02 · answer #8 · answered by Heckel 3 · 0⤊ 1⤋