I think it may either be K = 1 or K = 2
2006-09-16 10:00:08 · 14 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
K=4/3
Remember, nth root is the same as raising to the 1/nth power, thus you have (x^4)^(1/3), which is the same as x^(4/3).
2006-09-16 10:03:04 · answer #1 · answered by Pascal 7 · 1⤊ 3⤋
K=4/3 ...
How can it be 1 or 2 ?
2006-09-17 10:02:50 · answer #2 · answered by Innocence Redefined 5 · 0⤊ 2⤋
k=4/3
2006-09-16 17:09:12 · answer #3 · answered by bruinfan 7 · 3⤊ 1⤋
4/3
2006-09-16 17:16:11 · answer #4 · answered by angel_catz 1 · 3⤊ 1⤋
Assuming X and K are whole numbers, here we go. The mistake I've seen some people make is multiplying the value of x like this - X x 3 x 3. WRONG!! A cube is a number multiplied by itself 3 times - X x X x X. If the cube root of X is greater than 4 and we are dealing with whole numbers, then the cube root of X is 5 or more. The value of X would then be 125. Plug this into your formula and 125 > K
2006-09-16 17:22:40 · answer #5 · answered by GAB & R 2 · 1⤊ 4⤋
Looks like 4/3 to me. X^(4/3)....the 4 is the exponent, and the 3 is the cube root.
2006-09-16 17:04:05 · answer #6 · answered by Shaun 4 · 2⤊ 2⤋
Cubed root of x^4 = (x^4)^(1/3) = x^((4*(1/3))=x^(4/3)
k=4/3
2006-09-16 17:05:08 · answer #7 · answered by nospamcwt 5 · 3⤊ 2⤋
It's 4/3.
2006-09-16 17:01:43 · answer #8 · answered by Anonymous · 2⤊ 5⤋
cubed root of x is x^(1/3)
so cubed root of x^4 is (x^4)^(1/3)
myltiply 4 by (1/3) it will be 4/3
so x^(4/3)=x^k
then k= 4/3
2006-09-16 17:25:28 · answer #9 · answered by Anonymous · 3⤊ 1⤋
assume that you know the algebraic exponent rules...
such as (x^n) ^ m = x ^ nm etc
cube root of y = y^1/3 and so cube root of (x^4) is (x^4) ^ 1/3 = x^4/3 = x^k and hence k=4/3...
please tell us how you thought k=1 or k=2... there must be some logic... eager to know it !
2006-09-16 17:18:20 · answer #10 · answered by m s 3 · 2⤊ 2⤋