Go to http://infospace.com/
Click on reverse search and enter the phone #. If it is in their database it will give you the address as well as the name of the person.
2006-09-16 10:05:29
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answer #1
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answered by zora w 1
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If someone has hurt you, or has threatened you, contact the police with the number and details without giving your name, although if I was in danger, I wouldn't hesitate. If however you are trying to trace someone that you shouldn't be, I'd rather not talk to you. If you are trying to trace a long lost family member - good luck.
2006-09-16 10:40:55
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answer #2
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answered by Anonymous
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Well for one thing the Police will trace it but they will not give you that information and a crime has to be committed before they trace anyway.Have you tried 411 to see if the number is listed.
2006-09-16 10:08:47
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answer #3
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answered by ? 3
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Why are you interested in even doing this? Is this a phone number or address? Sounds like you are trying to stalk someone. Watch your step. The consequences of this are dire.
2006-09-16 09:58:21
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answer #4
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answered by Anonymous
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call the number and ask for the address ... pretend you're the phone company or a gas/electric company doing some research
2006-09-16 09:58:25
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answer #5
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answered by Marinersfan 5
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use a reverse directory available at the library.
2006-09-16 10:10:24
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answer #6
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answered by snddupree 5
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push *69 duumy white
2006-09-16 10:00:09
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answer #7
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answered by Anonymous
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These links will help you
http://people.yahoo.com/
http://www.freeprf.com/
http://www.reunitetonight.com/
http://family.public-records.com/...
http://www.192.com/
http://in.members.yahoo.com/regional/cou...
http://www.b4usearch.com/
http://www.peoplefinders.com/
http://www.zabasearch.com/
http://www.emailaddresses.com/
http://in.members.yahoo.com/interests/co...
http://spaces.live.com/
http://www.anywho.com/
http://www.addresses.com/
http://find.intelious.com/
Good luck and take care
2006-09-16 09:58:59
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answer #8
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answered by Anonymous
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try this web site:
http://www.reversephonedirectory.com/
2006-09-16 10:08:21
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answer #9
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answered by eeeeeeeeclipse 4
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