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how do you come up with atleast 6 values for a cubic expression?

The expression is an^3+bn^2+cn+d

2006-09-16 09:39:26 · 3 answers · asked by BENNETH[[98]] 2 in Science & Mathematics Mathematics

I dont get it please be more especific

2006-09-16 10:37:46 · update #1

3 answers

For example, let a=1;b=1;c=1;d=1
Now you have the equation: n^3+n^2+n+1

2006-09-16 10:50:07 · answer #1 · answered by bruinfan 7 · 0 0

"n" would have to be at least a quadratic equation for you to get at least 6 values, for ex:

2(x^2 + 5x + 6)^3 + 4(x^2 + 5x + 6)^2 + 8(x^2 + 5x + 6) + 16

will give you 6 values, of which will all be complex values, but i think you get the idea.

2006-09-16 18:16:46 · answer #2 · answered by Sherman81 6 · 0 0

n=0
d
n=1
a+b+c+d
....
you get the point

2006-09-16 17:36:01 · answer #3 · answered by ioana v 3 · 0 0

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