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this question is relative to f(x)=20+16x-x^2/4+x^2. This one has really got me stuck, is this the same as finding the area under a graph?

2006-09-16 09:18:42 · 4 answers · asked by Rach H 1 in Science & Mathematics Mathematics

4 answers

The roots of the function are -4 and 1. The indefinite integral of the function is:

4(3 + 2x)/(4 + x^2)

and the definite integral equals to 5. That's the area.

2006-09-16 11:32:40 · answer #1 · answered by Dimos F 4 · 0 0

Put f(x) =0 then x=1 and x=- 4
Now integrate the 8(4+x)(1-x)/(4+x^2)^2 with respect to x from the limits -4 to 1 you will get the answer

2006-09-16 17:09:34 · answer #2 · answered by Amar Soni 7 · 0 0

Also, finding the area bounded by the x-axis means it has to be between the 2 points that intercept on the x-axis, right?

So, what 2 points do you think they are?

2006-09-16 17:08:38 · answer #3 · answered by yljacktt 5 · 0 0

Yes. You need to carry out an integration of the function, for the given range.

2006-09-16 16:25:12 · answer #4 · answered by islamomt 2 · 0 0

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