The length of a rectangle is 3 times the width. The perimeter is 96 cm. Find the width and the length.?

Answer 1

where width is x and length is 3x
2L+2W=P
2(3x)+2(x)=96
6x+2x=96
8x=96
/8 /8
x=12

3x=L
3(12)=L
36=L

width = 12cm
length=36cm

hope this helps!

Answer 2

Just set this up as an equation. There is only one unknown because we know the length is 3 times the width. So if the unknown width is x, then the length is 3x.
The perimeter of the rectangle is twice the width plus twice the length. So x + x + 3x + 3x is the perimeter. This gives us the equation: 8x = 96 so x=12 is the width.
The length is then 3 times 12 = 36

Answer 3

let the width be=x
then the lengthbecomes=3x
perimeter of a rectanglr =2(L+B)
=2(3x+x)
perimeter given=96cm
96=2(3x+X)
96=6x+2x
96=8x
x=96/8
=12
x=12; x is the width so width is 12
and 3*12=36 is the length
=

Answer 4

12 cm by 36 cm

Here is how to solve the problem:

Let the short side be represented by the unknown X. The long side becomes 3X. The perimeter is simply the sum of the 4 sides, 1X + 3X + 1X + 3X = 96cm. Combining like terms gives 8X=96 cm, divide each side by 8 gives X=12 cm, substituting into 3X, we get 36 cm, thus making the rectangle 12 cm by 36 cm.

Answer 5

width 12
length 36

Answer 6

L=3W
96=2(L+W)
L=?
W=?

96=2(3W+W)
96/2=4W
48=4W
W=12 cm.
L=3W=3.12=48 cm.