f(x) = |x + x^3|
2006-09-16 06:52:58 · 8 answers · asked by Mist 1 in Science & Mathematics ➔ Mathematics
even
2006-09-16 06:55:03 · answer #1 · answered by selket 3 · 0⤊ 1⤋
If the entire function is in the absolute value, then it is always even. Without the absolute value, this function would be odd, because of the cubed variable.
2006-09-16 06:58:25 · answer #2 · answered by TychaBrahe 7 · 0⤊ 1⤋
In this state, this function is an even one.
2006-09-16 07:39:13 · answer #3 · answered by Anonymous · 0⤊ 1⤋
even this odd function is an even function, oddly
2006-09-16 08:23:44 · answer #4 · answered by m s 3 · 0⤊ 1⤋
This function is even.
For even function,
f(x)=f(-x)
f(-x) = | -x + (-x)^3 |
= | -(x+x^3) |
=|x+x^3|
=f(x)
2006-09-16 06:56:33 · answer #5 · answered by Anonymous · 1⤊ 0⤋
if f(x)=f(-x), then f(x) is even function.
f(-x)
=|(-x)+(-x)^3|
=|-(x)+-(x)^3|
=|-1(x+x^3)|
=|-1||x+x^3|
=|x+x^3|
=f(x)
It an even function, my friend.
2006-09-16 07:11:34 · answer #6 · answered by ctyuang 1 · 1⤊ 0⤋
Even, f(x)=f(-x).
2006-09-16 07:07:02 · answer #7 · answered by msi_cord 7 · 0⤊ 1⤋
neither
2006-09-16 06:57:51 · answer #8 · answered by Anonymous · 0⤊ 1⤋